Don said:
If someone is going to get a bit creative and make a spinner-powered
tire pump, why not make the piston diameter 1/8 inch? That takes .37
pound. For that matter, how about 1/16 inch? That takes a bit over .09
pound of force.
Now, let's say you have .3 G braking and a ring-shped flywheel "spinner"
of diameter 60% of that of the tire. More like a big ring than "bling",
but this is for function and angineering calculations - it could
concievably be "blinged up" afterwards.
Ring with points accelerating (even if negatively) by .18 G only needs
to weigh a little over half a pound to have such
acceleration/decelleration provide enough force to push a 1/16 inch
diameter column of air 30 PSI above atmosphere.
Let's say the pump has a stroke of 1 inch, a bore of 1/16 inch diameter,
meaning volume of about 1/325 cubic inch. Let's say that a 35 to zero
braking at .3 G occurs 4 times a day, a 25 to zero braking occurs 6 times
a day and a 55 to 20 MPH braking occurs twice a day, 6 days a week. (Of
course I am pulling numbers out of a hat, probably on the conservative
side, for "typical driving".)
This adds up to 55 seconds a day if braking at .3 G, with average speed
reduction of 30 MPH per braking. I would consider the available kinetic
energy from the flywheel to be 1/2 times its mass (if in form of a ring)
times square of speed reduction of braking. So I would use half this 30
MPH braking figure for effective flywheel speed for calculating average
RPM of a pump shaft during braking.
15 MPH and 6 feet means 3.67 revolutions per second. Times 55 seconds
of braking a day, is 201-202 revolutions. Even if the pump has only
one cycle per cycle of flywheel outrunning the tire, that is 201-202
strokes. This is roughly 5/8 cubic inch of air for 1/16 inch diameter
bore, 1 inch stroke.
If the flywheel output to the pump is only 1.5 or so inches from the
centerline of the axle, a half pound ring flywheel, it will deliver enough
force to push a 1/8 inch diameter column of air 30 PSI above atmosphere.
That means 2.5 cubic inches a day. If the pump has so much drag with a
small bore to need force double or triple that required just to push the
air, make the flywheel a ring of 1 to 1.6 pounds.
If my back-of-the envelope calculations are correct, 2.5 cubic inches
a day should be sufficient to make up a leak loss of 10 psig per year.
Most of the following patents have calculations showing the
feasability of extracting energy from wheel rotation and using
it to inflate tires.
http://www.patentstorm.us/patents/[ Patent Number].html
United States Patent 5409049 April 25, 1995
Tangential tire pressurizing and regulating apparatus
US Patent Issued on April 25, 1995
United States Patent 5452753
Vehicle tire management system including wheel with
self-contained tire inflation/deflation apparatus
US Patent Issued on September 26, 1995
http://www.patentstorm.us/patents/5452753.html
United States Patent 5355924
Vehicle wheel including self-inflating mechanism
US Patent Issued on October 18, 1994
http://www.patentstorm.us/patents/5355924.html
United States Patent 5556489
Wheel-mounted tire inflator
US Patent Issued on September 17, 1996
http://www.patentstorm.us/patents/5556489.html
United States Patent 5558730
Vehicle wheel including self-inflating tire pump
US Patent Issued on September 24, 1996
United States Patent 5591281
Flywheel tire inflation device
US Patent Issued on January 7, 1997
United States Patent 5667606
Tire pressurizing and regulating apparatus
US Patent Issued on September 16, 1997
United States Patent 5707215
Tuned resonant oscillating mass inflation pump and
method of extracting electrical energy therefrom
US Patent Issued on January 13, 1998
United States Patent 5941692
Tuned resonant oscillating mass inflation pump and
method of extracting electrical energy therefrom
US Patent Issued on August 24, 1999
United States Patent 5846354
Tire pressure maintenance system
US Patent Issued on December 8, 1998
United States Patent 5947696
Wheel mounted tire pump with a reciprocating piston
US Patent Issued on September 7, 1999
United States Patent 5975174
Rim mountable tire inflation maintenance device
US Patent Issued on November 2, 1999
United States Patent 6474383
Automotive wheel with improved inflation system
US Patent Issued on November 5, 2002
United States Patent 6744356
Tire pressure maintenance and monitoring system
US Patent Issued on June 1, 2004
United States Patent 6994136
Wheel end tire air pump
US Patent Issued on February 7, 2006
United States Patent 7237590
Tire pressure maintenance device
US Patent Issued on July 3, 2007