J
jasen
Wimshurst, is one design, here's another, it is a Bonetti Machine.
Then there is the sectorless Wimshurst.
The metal foil plates of which you speak, do not exist.
Other than that, you have overlook fine detail, the direction of force
is 90 degrees,
and as charge plate approaches the collector,
BULLSHIT. it's not EXACTLY 90 degrees.
Approximations will lead you the wrong way if you're looking for
free energy.
the force
of attraction is equal to the drag of the previous plate moving away.
the charge is less the force is less.
The charged plate is attracted to the opposite pole, when the collector
aquires that energy, there is an equal amount of attraction developed.
That energy isn't lost, or gained.
say what?
It strictly straight to the plate,
and straight away from the plate, the collectors draw on a plate that
approches, by as much as one that is moving away. There is no gain or
loss attributed to anything that is parallel to the axis of rotation.
The movemment of charges isn't parallel to the axis.
A magentic field, if lets say north faced north, would oppose the
direction of rotation, and there would be loss, if there is enough
inertial energy to get past the magnet, it will only push as hard to
move it away, and continue rotation in the same direction. With just
two permanent magnets, there would be a very significant loss at the
point where the interia of rotation dropped below the field strength of
the magnets pushing against each other because, at that point, the
rotation would stop. The force of attraction of north and south poles
works the same way, except that magnets will center themselves over the
other aligned.
what have magnets to so with anything here?
use shorter sentences if you want to be understood. as it is you are
starting to come across as a kook.
The dielectric of the rotating disk, retains the same charge in volts,
and that field always pulls equal on the Sectorless machines, and
parallel to the axis of rotation. It pulls on the opposite charge as
it approches, and pushes on the like charge as it leaves.
The dielectric isn't all that signinficant here,
and learn to post correctly.