Wireless Distance Proportional Signal Circuit Help

[anudeep2011]

I need help in wireless Distance proportional Signal System

What i need is clearly explained in this diagram

Now, What i need is two circuits A and B

As show in the diagram B must be a emitter or watever
A must get the signals from B and must display (or output a value to Micro Processor) which is proportional to the distance between A and B.
So when i move the circuit B .. the value in A must change accordingly

I need your suggestions and help
I am a complete Noob in this, I am from Computers department

Hoping for help
Thanks



( Sorry , If I posted in wrong forum )

 

[(*steve*)]

1) B has a GPS and transmits it's location to A

2) A "beeps" every (say) second, and B responds to the beep with another frequency beep. A tracks the time between sending it's beep and receiving a response. (this will give distance only, not direction)

3) B has a large orange ball on it. A has a camera and pans the environment looking for the orange ball. When it finds it, it uses the apparent size and angle to calculate B's relative position.

 

[anudeep2011]

1) i already had the idea of gps,bt its of no use
3)this type wont suit

2) i wud lyk to noe more abt this beep method. distance is al what i need. and atmost 20ft

thanks

 

[anudeep2011]

waiting for someone to help :\

 

[donkey]

create 2 tancievers. when point b reicieves the signal from point A it then transmits back another signal hopefully a different code or frequency to stop it "bouncing" of objects and giving a false reading.
you then have point A calculate the time from when it beeped to when it recieved the second signal. and multiply that by the speed of the wavelength divide it by 2 and it should give a measurement. I can tell you the principles involved, but as for a schematic thats a bit beyond me at this juncture.

 

[anudeep2011]

Thanks a lot for your reply
I very clearly understood the idea but ya dont noe anything related to implement
Moreover,If the same is to be done with 2 Fixed points(now its only one A) which are at some distance .Then both the Fixed Circuits must send 2 different waves? Or some other Idea?

create 2 tancievers. when point b reicieves the signal from point A it then transmits back another signal hopefully a different code or frequency to stop it "bouncing" of objects and giving a false reading.
you then have point A calculate the time from when it beeped to when it recieved the second signal. and multiply that by the speed of the wavelength divide it by 2 and it should give a measurement. I can tell you the principles involved, but as for a schematic thats a bit beyond me at this juncture.

 

[duke37]

I suggest using an ultrasonic transducer to generate a pulse and a similar transducer to receive the pulse. It may be possible to use a reflector at point B rather than an active device. You will need to research how the transducer is driven and make a simple circuit to drive it.

If you wish to find the position of point B, you will need triangulation using point A1 and A2. Each A point should inhibit its output for a short time when it receives a pulse from Ax to stop signal confusion.

An analog circuit could be made to output a voltage proportional to distance but you would need digital data to calculate position.

This not a simple project and will need instrumentation and development.

What is your native language?

 

[(*steve*)]

2) i wud lyk to noe more abt this beep method. distance is al what i need. and atmost 20ft

What is your native language?

Clearly not English.

As mentioned by someone else, you simply have the main transmitter (A) send beeps at some suitable interval. These beeps might be a 40kHz signal and may last for (say) 1 ms. When B hears a beep, it immediatly transmits a beep (say another 40kHz 1 ms beep). A records the time between when it sends the first beep and when it receives the second. This time is proportional to the distance between A and B.

There are some complicating factors.

Firstly, A might hear a reflection of its own beep before it hears B's response. In order to ignore this, you might have B;s response differ in some recognisable way, say frequency, but also possibly modulation. This is also the reson the system is active. It allows A to discriminate between B and a reflection off some other hard surface.

Second, echos may mean that B hears A's beep several times (directly, bounced via a side wall, bounced via an end wall) and A may hear B's response several times for the same reason. Both circuits need to respons to the *first* beep they hear, then ignore all subsequent beeps for some short duration (less than the interval between beeps)

 

[duke37]

Maplin have an ultrsonic sonar ranging IC - N17KK.

 

[anudeep2011]

Clearly not English.

As mentioned by someone else, you simply have the main transmitter (A) send beeps at some suitable interval. These beeps might be a 40kHz signal and may last for (say) 1 ms. When B hears a beep, it immediatly transmits a beep (say another 40kHz 1 ms beep). A records the time between when it sends the first beep and when it receives the second. This time is proportional to the distance between A and B.

There are some complicating factors.

Firstly, A might hear a reflection of its own beep before it hears B's response. In order to ignore this, you might have B;s response differ in some recognisable way, say frequency, but also possibly modulation. This is also the reson the system is active. It allows A to discriminate between B and a reflection off some other hard surface.

Second, echos may mean that B hears A's beep several times (directly, bounced via a side wall, bounced via an end wall) and A may hear B's response several times for the same reason. Both circuits need to respons to the *first* beep they hear, then ignore all subsequent beeps for some short duration (less than the interval between beeps)

Thanks

What if there are two Points A1 and A2 from which the distance of B is to be measured ?
In that case B will not be able to recognize weather A1 or A2 gave the reply pulse

 

[anudeep2011]

What is your native language?

I am from India
Telugu is my native language

 

[duke37]

A1 and A2 can send a signal alternately. B does not need to know where this signal comes from, it just has to respond quickly. Both A1 and A2 will need connecting to an analysing system to calculate position.

Note that there will be two possible positions, one in front of the line A1 to A2 and one behind. A third transmitter could be used to determine which is the correct one.

Note that the speed of sound varies with temperature and pressure and will need measuring if high accuracy is required.