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Why is Vbc = Vbe - Vce ?

I have seen in various places the equation Vbc = Vbe - Vce for NPN and
PNP transistors. It may seem obvious to others but I just don't see
how this is true. Could someone please throw me a bone? Thanks
 
R

Rich Webb

I have seen in various places the equation Vbc = Vbe - Vce for NPN and
PNP transistors. It may seem obvious to others but I just don't see
how this is true. Could someone please throw me a bone? Thanks

(Vb - Ve) - (Vc - Ve) = Vb - Ve - Vc + Ve = (Vb - Vc)
 
A

Andrew Holme

I have seen in various places the equation Vbc = Vbe - Vce for NPN and
PNP transistors. It may seem obvious to others but I just don't see
how this is true. Could someone please throw me a bone? Thanks


Vce = Vcb + Vbe

Vcb = Vce - Vbe

Vbc = Vbe - Vce

Polarity is important.
 
P

pimpom

I have seen in various places the equation Vbc = Vbe - Vce for
NPN and
PNP transistors. It may seem obvious to others but I just
don't see
how this is true. Could someone please throw me a bone?
Thanks

Maybe this will help. View the ASCII diagram with mono-spaced
font such as the WinXP default Lucida Console or Courier:

__ __
| | |
| | |
| | |
Vbc | |
| / |
| |/ |
|___| Vce
| |\ |
| \ |
| | |
Vbe | |
| | |
|__ | __|
 
J

Jasen Betts

I have seen in various places the equation Vbc = Vbe - Vce for NPN and
PNP transistors. It may seem obvious to others but I just don't see
how this is true. Could someone please throw me a bone? Thanks

Vbc = Vbe + Vec

from B to C is the same as from B to E and E to C

Kirchoffs node law.

Bye.
Jasen
 
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