Eric said:
I have three speaker wires running just behind sheetrock along a wall in my
house that have breaks in them somewhere (I believe from the contractor
firing nails through the wires when putting up the sheetrock). Two of the
wires are shorted from one end (wall terminal) and open from the other. The
third is open from both ends. I figure in all cases a nail-gunned nail went
through the wire in question, and in two cases the nail is probably shorting
one half of the wire.
You very well might be better off biting the bullet and
abandoning the wires, and rerunning them. If you have
access to the wall from above/below it could be worth
the effort.
Are these wires on the surface of the studs such that
when the rock was put up it pressed the wires between
the rock and the studs, or are they run through holes
bored in the studs - or are they vertical and stapled
to the sides of the studs?
I have a couple of "fears" about the practicality
of the repair, even assuming you can find the exact
location of the break/short.
1) You may not have enough slack in the wire at the
point where you make a hole in the wall to be able to
repair it, necessitating a bigger hole - or a second
hole.
2) You may have additional damage that hasn't shown
up yet that may necessitate future repairs.
Installing brand new runs eliminates both. When you
plan it, you'll know precisely where, and how big,
to make your holes. Obviously, I have no clue how
practical/impractal installing new runs would be
in your situation.
For a cheap, easy signal source you could try
connecting a 120 to 6 or 12 volt transformer
secondary to each pair of wires, one at a time
through a 1 K resistor. Then try to use a
transistor radio to detect the 60 cycle hum.
If that won't work, and audio amplifier with
a telephone pickup coil probably will. I don't
know how well that method will pinpoint the
source of the trouble, but it may be work trying.
An even better signal source could be made by
adding a triac circuit to the secondary and
setting it to produce say half the output
voltage.