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and how are you measuring current?
It sounds like you're measuring the current directly across the battery terminals, i.e. applying a short circuit to them. It won't do them a lot of good and will discharge them rapidly.
You measure current by placing the ammeter in series with the load (not across it)
Even if I did not measure the current correctly I tried to connect the bank directly to the converter it didn't work it was hot and there was smoke. What can explain that?
I'm sure the current did increase. That was kinda the point. You don't say if you had a load attached at the time.I believe that the current increased and the voltage.
Smoke is a bad thing. It is quite likely something is damaged beyond repair.I'll try this out and give you all some feedback.
Connecting it the wrong way around, measuring the current at the output (i.e. shorting the output), probably many other things too.
I'm sure the current did increase. That was kinda the point. You don't say if you had a load attached at the time.
Smoke is a bad thing. It is quite likely something is damaged beyond repair.
What exactly are you going to try out?
I would have connected the batteries to the regulator and with a very small load (say a 1k resistor) I would have set the output voltage. Then I would have connected the motor. Measuring the input current would also have been something I would have done at both steps to ensure odd things were not happening.
If your input voltage is around 5V and your output is 16V you would be expecting the input current to be more than three times the output current. (edit: a little more. So up to 4 times, certainly not more than 6 times)
You can't "charge it with higher current than it requires".
It will only draw the current it needs. If it was drawing excessive current it was because something was wrong. i.e. batteries around the wrong way, you measuring the current across the output, or something like that. Possibly you placed the PCB on a surface that shorted it out, maybe you damaged the board earlier, etc., etc.
Just the fact that the batteries *could* supply more current doesn't mean they will.
You need to find out what went wrong and make sure it doesn't happen again.
edit (again) you measure the current by placing an ammeter IN SERIES with your load, not in parallel with anything. With the batteries connected to the board and nothing connected to the output you should see a couple (maybe up to a few tens) of mA.
DO NOT place the ammeter across the batteries.
read this.
You don't need a battery "rated" at some particular current. That's just silly.
Which shows that I have overloaded the converter with high currents.
Need to find a higher voltage rating battery that has a perfect current range.
possibly. Maybe you shorted it out.
How many times do I need to tell you that this is PURE NONSENSE. The current the battery can supply is ONLY an issue if it's too low, OR if you do something stupid.
Feel free to ignore me though. What do I know?
Moha,
If you come here for advice, it helps if you listen to it. Steve is very knowlegable. What he is telling you is entirely correct and you simply ignore him. If you don't understand, ask for clarification. If you insist on arguing with people who know way more than you do, you might as well just do it on your own and continue to fail. If you really want hellp then listen to what the people here are telling you and try to understand it.
So I will second what Steve has said, you cannot supply too much current to a device if you are running it at the voltage it was designed for. Think of a lamp plugged into the wall in your home. If it has a 100W bulb (in the US) this takes approximately 1 Amp. But the same wall socket can provide 15A for a hair dryer. Why does the light bulb not blow up when you connect it to a 15 Amp supply? When you understand this, then youi can move forward.
The only reason your board did not smoke when you used a smaller battery is becuase it was not able to supply the current the board wanted. Which caused it to drop it's voltage. So the board was not operating at the voltage of the battery, it was operating at a lower voltage.
I addition to the possibilities that Steve has already suggested, I would say that there is another possibility. The motor is trying to draw more current than the converter is designed to provide. This might be because the output voltage you have set is too high. How do you set this voltage?
Bob