R
Rich Grise
OK, what's the relationship between R factor and thermal conductivity?
Have you tried google?
Good Luck!
Rich
OK, what's the relationship between R factor and thermal conductivity?
Where?
John
John Larkin a écrit :
Thermal resistance is in K/W, while you're speaking of K/W/ohm.
I wonder how this should be called.
Jim Thompson said:Several years ago, as an aside to another thermal question, I asked...
"Brings to mind a thing I've been pondering... what's the thermal
resistance of 3/4" plywood ?"
Never saw a response.
More specifically, a closed plywood box, inside dimensions of 8" x 11"
x 18".
Outside ambient of around 77°.
How many watts of dissipation inside of box to raise interior air
temperature to 95°F? (I might use a fan to circulate the air.)
If I made one wall of the box 1/8" glass (8" x 18" side), how much
change?
...Jim Thompson
--
| James E.Thompson, P.E. | mens |
| Analog Innovations, Inc. | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| Phoenix, Arizona 85048 Skype: Contacts Only | |
| Voice480)460-2350 Fax: Available upon request | Brass Rat |
| E-mail Icon at http://www.analog-innovations.com | 1962 |
I love to cook with wine Sometimes I even put it in the food
Jim Thompson said:Several years ago, as an aside to another thermal question, I asked...
"Brings to mind a thing I've been pondering... what's the thermal
resistance of 3/4" plywood ?"
Never saw a response.
From http://www.engineeringtoolbox.com/thermal-conductivity-d_429.html
about .13 W/mK is the thermal conductivity. So, about 7.7 mK/W resistivity.
More specifically, a closed plywood box, inside dimensions of 8" x 11"
x 18".
Outside ambient of around 77°.
How many watts of dissipation inside of box to raise interior air
temperature to 95°F? (I might use a fan to circulate the air.)
I estimate about 86 or so watts.
If I made one wall of the box 1/8" glass (8" x 18" side), how much
change?
Not much.
[snip]...Jim Thompson
Cheers,
John
...
Actually, the required wattage is probably between 20 and 40 watts.
As I mentioned in a previous post, 40W maintains close to the
desired temperature in a larger box:
"Here are some measurements from a light-bulb-heated food dryer with its
vents closed: Turned on a 40W bulb at 3pm, 75F. At 4:20, with 90F near
the middle of the box, turned off 40W bulb, turned on 60W bulb. At 5:20,
with 108F near the middle, turned off 60W bulb, turned on 40W bulb. At
10pm, 94F near the middle. This box is about 10"x11"x28" inside, or
twice the volume of your 8"x11"x18" box. 50% of its surface is 3/4"
wood, 35% is 1/8" masonite, and the rest is window glass."
Thermal resistance per ohm, just like I wrote it.
Most pure metals hit about the same value.
z.b. said:...
Actually, the required wattage is probably between 20 and 40 watts.
As I mentioned in a previous post, 40W maintains close to the
desired temperature in a larger box:
"Here are some measurements from a light-bulb-heated food dryer with its
vents closed: Turned on a 40W bulb at 3pm, 75F. At 4:20, with 90F near
the middle of the box, turned off 40W bulb, turned on 60W bulb. At 5:20,
with 108F near the middle, turned off 60W bulb, turned on 40W bulb. At
10pm, 94F near the middle. This box is about 10"x11"x28" inside, or
twice the volume of your 8"x11"x18" box. 50% of its surface is 3/4"
wood, 35% is 1/8" masonite, and the rest is window glass."
IIRC pure copper wins, but you have to use really really skinny screws.
Generally the winning scheme for running wires to some thermally
insulated thing is narrow trace Cu flex circuit, preferably with a
thermal ground at each cooling stage.
Cheers
Phil Hobbs
(Getting back to my parts lists now)
A rare moment of lucidity.OK, useful numbers, and right on-point... dryer application. I don't
want the light, so I'll just use big wirewounds bolted to a finned
heatsink/source ;-)
...Jim Thompson
Use big nylon nuts and bolts. Or glass filled epoxy.
Which don't conduct electricity very well.
John
You do not have to rely on the fasteners to provide the conduction path
between two mating surfaces. In fact, you shouldn't.
I thought you were talking about thermal conduction anyway.
Thompson is such an asshole, he doesn't really deserve an answer - whyFrom http://www.engineeringtoolbox.com/thermal-conductivity-d_429.html
about .13 W/mK is the thermal conductivity. So, about 7.7 mK/W resistivity.
That's because you've got all the smart people plonked. There were at
least a half-dozen good responses, but apparently the sand got in
your eyes.
Thompson is such an asshole, he doesn't really deserve an answer - why
the hell should we do his googling for him?
Thanks,
Rich
Rich Grise said:That's because you've got all the smart people plonked. There were at
least a half-dozen good responses, but apparently the sand got in
your eyes.
Thompson is such an asshole, he doesn't really deserve an answer - why
the hell should we do his googling for him?
Thanks,
Rich
Well, first of all, it's not my job to try to decide who deserves an answer
and who does not.
Second, I find that I learn things by trying to help others. So, it's
somewhat of a selfish motive, I guess.
You're welcome,
John
Aaaaah! Life is wonderful... I've been promoted to "asshole"! Are
there grades of "asshole", like "lieutenant asshole", or "rear admiral
asshole"... ?![]()
Sure, many of us are privates, but there are also general assholes,
like Slowman and DimBulb. ...and of course, the leftist fairies'
assholes aren't private at all.