I will breadboard the circuit and let you know.
Boy i have such a tiny knowledge on electronics that i dont even understand how the transistor works. I am not able to understand the circuit alone.
i wonder how i could change that ? for example i have read about transistors that explain how they are made but not how biasing affects their operation...
Here is a
very simplified explanation:
In the schematic above the transistor is used as a "switch" which has 2 states "on" and "off".
The functionality is of a logic inverter.
Unlike a "pure logic device" ,it has different input and output voltage levels i.e it performs voltage shifting/translation.
In the
"on" state of the Tr. ,the "switch" is closed and the output is 0-volts.
For that to happen the Tr. should be "foreword biased" into conduction(actually saturation).
That needs
VBE to be
higher than 0.5V(actually about 0.8V,with the help of the presence of the base resistors),
it will happen when the
input is in the "space" level( >+3v).
In the
"off" state of the Tr. ,the "switch" is open and the output is at VCC volts.
For that to happen the Tr. should be "reversed biased" into non-conduction.
That needs
VBE to be
lower than 0.5V(actually -0.7V due to the protective diode),
it will happen when the
input is in the "mark" level( <-3v).
Note :
If the input is open the condition of the Tr. is "off" !
(Self check:Can you explain why?)
That is basically the operation of an NPN bipolar transistor in a "digital circuit" functioning as a switch.
There are other applications where the Tr is used as Amplifier etc. in "analog circuits",
they are much more complicated to explain.
There is a lot of material about it on the WEB,and in EP as well .