Hey.
lets say I have 24 volts AC at 25KHz.
I have a transformer and I step it up to 2000 volts.
Then I feed it through a diode and into a capacitor.
The circuit has no load, the capacitor then charges and approaches 2000 volts, then my current draw from my 24 volt AC source decreases, and all I am drawing now is enough to maintain votage across this capacitor.
Assuming I have no load across the capacitor to discharge it while maintaining supply to it, My current draw will be very low, correct?
Question, because I have half wave 25KHz signal as my original AC and only 1 diode making it half wave rectification, can I attach an antenna to the (+) terminal of the capacitor and measure 25KHz half wave with a frequency analyzer in the same room? (Negate external noise and distance from the antenna to the meter).
With antenna attached, my capacitor will still be at 2000 volts?
Will my current draw from the source be very low assuming the capacitor reached full charge and the only thing attached is an antenna and no actual resistance load across the capacitor terminals?
I attached a drawing showing the simple circuit.
I basically want to know if adding the antenna will not create additional load and if I will read 25KHz off that antenna, even thought its on the pulsing DC (+) side.
lets say I have 24 volts AC at 25KHz.
I have a transformer and I step it up to 2000 volts.
Then I feed it through a diode and into a capacitor.
The circuit has no load, the capacitor then charges and approaches 2000 volts, then my current draw from my 24 volt AC source decreases, and all I am drawing now is enough to maintain votage across this capacitor.
Assuming I have no load across the capacitor to discharge it while maintaining supply to it, My current draw will be very low, correct?
Question, because I have half wave 25KHz signal as my original AC and only 1 diode making it half wave rectification, can I attach an antenna to the (+) terminal of the capacitor and measure 25KHz half wave with a frequency analyzer in the same room? (Negate external noise and distance from the antenna to the meter).
With antenna attached, my capacitor will still be at 2000 volts?
Will my current draw from the source be very low assuming the capacitor reached full charge and the only thing attached is an antenna and no actual resistance load across the capacitor terminals?
I attached a drawing showing the simple circuit.
I basically want to know if adding the antenna will not create additional load and if I will read 25KHz off that antenna, even thought its on the pulsing DC (+) side.