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By any chance, could you look at the oscilloscope settings? are they correct?
Is it because it was set to AC? Im using DC!
Oh I am using a power supply and the ground is connected to this power supply. I have common ground troughout the circuit.
How can I use a ground compatible with the oscilloscope? Hmmph this is a computer oscilloscope and I dont have other options... but I do have a reference pin on the DSO2090 ... maybe that can be used?
So the attached circuit schematic is not alone in the circuit. It is replicated for 8 times and so I have it identically in the same circuit connected together only by 12V Test, 12V Live and Ground.
That is correct, you will see some slight conductance via the resistors as I pointed out earlier.1. When the circuit is on 12V Test (no ignitors) the green LEDs all light up dimmly
Again, as expected.2. Same with 12V Live and no ignitors (the red LEDs all light up dimmly.
Think of it as a dim LED indicating power but no ignitor. (it's a feature )The above are understood but have no solution
The answer is, it shouldn't, and I would suspect a wiring error.HOWEVER the following is a mystery:
3. When the system is on 12V Test and I insert JUST ONE ignitor, ALL 8 green LEDs light up bright! What is going on? I mean the only thing which is common to all 8 circuits is supply... how come one ignitor is affecting all 8 outputs?
The first test, with all power removed (and no ignotors) is to measure the resistance between a pair of connections for ignitors (the non-ground ends). The resistance should be in the order of 60k
edit: a simple test would be to insert a (say) 47 ohm resistor in place of the ignitor (again the LEDs should light up) but then change over to the 12V supply for just this channel. If I am right, the red LED will light up for this channel, and the other green LEDs will all turn off (well, back to dim).
the easiest way to fix the LEDs is (probably) to place a diode in series with the anodes of the LEDs and then place a 2k2 resistor across the LEDs
The diodes will prevent current flowing back into the open 12V supply (may not be required). The resistors across them keep the voltage across them lower than their turn-on voltage when they have 35k to ground.
Breadboard it first.