J
John Fields
Ooops. I misspoke. They are not quite the same.
Ooops. I misspoke. They are not quite the same.
Quite counter intuitive, I agree, but none-the-less true.
To convince myself, I once created an Excel spreadsheet
to demonstrate the fact.
It along with some other discussion and plots are available
here http://keith.dysart.googlepages.com/radio5
To get exactly the same results, if, at time t0, the phases
for the signals being multiplied together are 0, then at
time t0, the initial phases for the signals being added
must be 90 and -90.
isw said:After you get done talking about modulation and sidebands, somebody
might want to take a stab at explaining why, if you tune a receiver to
the second harmonic (or any other harmonic) of a modulated carrier (AM
or FM; makes no difference), the audio comes out sounding exactly as it
does if you tune to the fundamental? That is, while the second harmonic
of the carrier is twice the frequency of the fundamental, the sidebands
of the second harmonic are *not* located at twice the frequencies of the
sidebands of the fundamental, but rather precisely as far from the
second harmonic of the carrier as they are from the fundamental.
Isaac
Brenda Ann said:I can't speak to second harmonics of a received signal, though I can't think
why they would be any different than an internal signal.. but:
When you frequency multiply and FM signal in a transmitter (As used to be
done on most FM transmitters in the days before PLL came along), you not
only multiplied the extant frequency, but the modulation swing as well. i.e.
if you start with a 1 MHz FM modualated crystal oscillator, and manage to
get 500 Hz swing from the crystal (using this only as a simple example),
then if you double that signal's carrier frequency, you also double the FM
swing to 1 KHz. Tripling it from there would give you a 6 MHz carrier with a
3 KHz swing, and so on.
Keith Dysart said:Ooops. I misspoke. They are not quite the same.
The spectrum is the same, but if you want to get exactly
the same result, the lower frequency needs a 90 degree
offset and the upper frequency needs a -90 degree offset.
And the amplitudes of the the sum and difference
frequencies need to be one half of the amplitude of
the frequencies being multiplied.
...Keith
Keith Dysart said:Ooops. I misspoke. They are not quite the same.
The spectrum is the same, but if you want to get exactly
the same result, the lower frequency needs a 90 degree
offset and the upper frequency needs a -90 degree offset.
And the amplitudes of the the sum and difference
frequencies need to be one half of the amplitude of
the frequencies being multiplied.
...Keith
You win.
When I conceived the problem I was thinking
cosines actually. In which case there are no
phase shifts to worry about in the result.
I also forgot the half amplitude factor.
While it might not be obvious, the two cases I
described are basically identical. And this
situation occurs in real life, i.e. in radio signals,
oceanography, and guitar tuning.
It follows from what is taught in high school
geometry.
cos(a) * cos(b) = 0.5 * (cos[a+b] + cos[a-b])
Basically: multiplying two sine waves is
the same as adding the (half amplitude)
sum and difference frequencies.
(For sines it is
sin(a) * sin(b) = 0.5 * (cos[a-b]-cos[a+b])
= 0.5 * (sin[a-b+90degrees] - sin[a+b+90degrees])
= 0.5 * (sin[a-b+90degrees] + sin[a+b-90degrees])
)
Ian Jackson said:For multiplying FM, yes, of course, this is exactly what happens. And as
it happens for FM, it must also happen for AM.
Ron Baker said:You win.
When I conceived the problem I was thinking
cosines actually. In which case there are no
phase shifts to worry about in the result.
I also forgot the half amplitude factor.
While it might not be obvious, the two cases I
described are basically identical. And this
situation occurs in real life, i.e. in radio signals,
oceanography, and guitar tuning.
Ian Jackson said:(b) In the second scenario, the 2nd harmonic is effectively present
BEFORE modulation, so it gets modulated along with the fundamental. In
this case, the lower frequencies of sidebands of the 2nd harmonic will
be 'normal', and the signal will sound normal.
After you get done talking about modulation and sidebands, somebody
might want to take a stab at explaining why, if you tune a receiver to
the second harmonic (or any other harmonic) of a modulated carrier (AM
or FM; makes no difference), the audio comes out sounding exactly as it
does if you tune to the fundamental? That is, while the second harmonic
of the carrier is twice the frequency of the fundamental, the sidebands
of the second harmonic are *not* located at twice the frequencies of the
sidebands of the fundamental, but rather precisely as far from the
second harmonic of the carrier as they are from the fundamental.
Isaac
Don Bowey said:On 7/4/07 7:52 AM, in article [email protected],
"Ron
cos(a) * cos(b) = 0.5 * (cos[a+b] + cos[a-b])
Basically: multiplying two sine waves is
the same as adding the (half amplitude)
sum and difference frequencies.
No, they aren't the same at all, they only appear to be the same before
they are examined. The two sidebands will not have the correct phase
relationship.
One could, temporarily, mistake the added combination for a full carrier
with independent sidebands, however.
(For sines it is
sin(a) * sin(b) = 0.5 * (cos[a-b]-cos[a+b])
= 0.5 * (sin[a-b+90degrees] - sin[a+b+90degrees])
= 0.5 * (sin[a-b+90degrees] + sin[a+b-90degrees])
)
isw said:The beat you hear during guitar tuning is not modulation; there is no
non-linear process involved (i.e. no multiplication).
Isaac
The beat you hear during guitar tuning is not modulation; there is no
non-linear process involved (i.e. no multiplication).
---
That's not true.
The human ear has a logarithmic amplitude response and the beat note
(the difference frequency) is generated there. The sum frequency is
too, but when unison is achieved it'll be at precisely twice the
frequency of either fundamental and won't be noticed.
Don Bowey said:On 7/4/07 7:52 AM, in article [email protected],
"Ron
cos(a) * cos(b) = 0.5 * (cos[a+b] + cos[a-b])
Basically: multiplying two sine waves is
the same as adding the (half amplitude)
sum and difference frequencies.
No, they aren't the same at all, they only appear to be the same before
they are examined. The two sidebands will not have the correct phase
relationship.
What do you mean? What is the "correct"
relationship?
One could, temporarily, mistake the added combination for a full carrier
with independent sidebands, however.
(For sines it is
sin(a) * sin(b) = 0.5 * (cos[a-b]-cos[a+b])
= 0.5 * (sin[a-b+90degrees] - sin[a+b+90degrees])
= 0.5 * (sin[a-b+90degrees] + sin[a+b-90degrees])
)
When AM is correctly accomplished (a single voiceband signal is modulated
onto a carrier via a non-linear process), at an envelope detector the two
sidebands will be additive. But if you independe ntly place a carrier at
frequency ( c ), another carrier at ( c-1 khz) and another carrier at (c+ 1
kHz), the composite can look like an AM signal, but it is not, and only by
the most extreme luck will the sidebands be additive at the detector. They
would probably cycle between additive and subtractive since they have no
real relationship and were not the result of amplitude modulation.
When AM is correctly accomplished (a single voiceband signal is modulated
onto a carrier via a non-linear process), at an envelope detector the two
sidebands will be additive. But if you independe ntly place a carrier at
frequency ( c ), another carrier at ( c-1 khz) and another carrier at (c+
1 kHz), the composite can look like an AM signal, but it is not, and only
by
the most extreme luck will the sidebands be additive at the detector.
They would probably cycle between additive and subtractive since they have
no real relationship and were not the result of amplitude modulation.
A peak detector is best understood in the time domain, try to create a
simple description in the frequency domain and you can only cause confusion
and incorrect conclusions.
Don said:You appear to be confused. I established a set of conditions, which
necessarily describe
the frequencies a how they originate.
What domain is used for analysis is left to the reader. I can see the
results I described, equally in the two domains.
Or did I miss a point about your post?
Don Bowey said:Don Bowey said:On 7/4/07 7:52 AM, in article [email protected],
"Ron
Baker, Pluralitas!" <[email protected]> wrote:
cos(a) * cos(b) = 0.5 * (cos[a+b] + cos[a-b])
Basically: multiplying two sine waves is
the same as adding the (half amplitude)
sum and difference frequencies.
No, they aren't the same at all, they only appear to be the same before
they are examined. The two sidebands will not have the correct phase
relationship.
What do you mean? What is the "correct"
relationship?
One could, temporarily, mistake the added combination for a full carrier
with independent sidebands, however.
(For sines it is
sin(a) * sin(b) = 0.5 * (cos[a-b]-cos[a+b])
= 0.5 * (sin[a-b+90degrees] - sin[a+b+90degrees])
= 0.5 * (sin[a-b+90degrees] + sin[a+b-90degrees])
)
When AM is correctly accomplished (a single voiceband signal is modulated
The questions I posed were not about AM. The
subject could have been viewed as DSB but that
wasn't the specific intent either.