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Or use the common equation for a voltage divider.You can find the current from the total voltage and the total resistance.
Then calculate the voltage across each resistor and find U+ relative to one end and then shift the reference to the common.
The important thing to consider is the impedance of the Opamp's input in comparison to the resistors' values...Hello I was wondering how the approach is to solve this exercise?
When I used the voltage divider law:
(7,5+12,5)*3/20+10 = 2 V
I know this is wrong, could someone explain too me why?
The important thing to consider is the impedance of the Opamp's input in comparison to the resistors' values...
Thank you for a good answer. Maybe this question is very easy anyhow, how do you find "Total voltage across R5 and R6". Why do you need solve only the voltage drop across R5, why not R5+R6?Break it down into simple steps.
Total resistance of R5 and R6.
Total voltage across R5 and R6.
Current through R5 and R6.
Voltage drop across R5. subtract that from +10 V.
Thank you for a good answer. Maybe this question is very easy anyhow, how do you find "Total voltage across R5 and R6". Why do you need solve only the voltage drop across R5, why not R5+R6?
Rotal = 7,5+12,5 =20 ohm
The input ompedance of an ideal opamp is infinity, that's why it is of no concern and that was where I was hinting at.Why? It doesn't tell you what the op amp is so there is no way to know. Given an ideal op amp, the impedance of the op amp is of no concern.