Untill now, my sources for the reaction of light on silver chloride
claimed that UV light was needed to knock an electron loose from the
chlorine.
However, I just discovered the following entry that shows the
reaction is stronger at UV, but it still occurs even with red light:
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After hearing about William Herschel's discovery of infrared light
in 1800, Johann Ritter decided to see if he could detect light
beyond the other end of the spectrum - past violet. In 1801, he was
experimenting with silver chloride, which turned black when exposed
to light. He had heard that blue light caused a greater reaction in
silver chloride than red light did and decided to conduct an
experiment to see if this was indeed true. Ritter directed sunlight
through a glass prism to create a spectrum and then placed silver
chloride in each color. He found that the silver chloride
increasingly darkened from the red to the violet part of the
spectrum as predicted. Ritter then decided to place silver chloride
in the area just beyond the violet end of the spectrum in a region
where no sunlight was visible, and was amazed to see an even more
intense reaction there. This experiment showed for the first time
that an invisible form of light existed beyond the violet end of the
visible spectrum. This is now know as the ultraviolet part of the
electromagnetic spectrum.
http://coolcosmos.ipac.caltech.edu//cosmic_classroom/classroom_activities
/ritter_example.html
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I am very pleased to find this out. I was about to invest some time
on an instrumentation project that would have not worked the way I
planned
Regards,
Mike Monett