I have a motor control PCB from a ground source heat pump that has a visibly blown component. I would like it identified and to now how it would effect the boards performance as a whole.
I have very limited electronics knowledge. The component is marked z1 on the PCB. The board controls a 230v ac pump.
Picture to follow. I have made an attempt at a circuit diagram.
VDR - Voltage Dependent Resistor, for suppression, often when they do their job, they are sacrificed in the process!
The circuit should work without it for trial purposes.
M.
I use 275L40, look up the Littlefuse VDR spec sheet, it shows operating voltage and Joule value, in the example the Joule rate is 40.
Available on DigiKey
M.
Replaced the variresistor with Z250F 275v 65 joules rating. The new component started over heating almost immediately power was applied. Is it likely we have other damaged components on this board. The mains voltage here is 245volts.
This type is rated for 230 V mains only, see here. Unfortunately no datasheet there
Mains voltage is typically +-10 % at the least, use +-20 % for worst case. This means your mains can actually reach up to 294 V. The varistor should withstand this voltage without becoming conductive. You also have to take into account worst case tolerances and temperature degradation of the varistor. I suggest you use a min. 320 VRMS varistor.
Thanks for the timely response.. We are exploring a step down transformer to reduce the main to 220 volts as this heat pump is Italian in origin and is built fo continental voltage levels.