Yes, Vbe determines Ib if one drives the base-emitter junction with a voltage source, since that makes Vbe the independent variable and Ib dependent. But a circuit designer does not drive the base-emitter junction with a voltage source.
I cannot resist to reply to this (false) statement again. Didn`t you read my earlier posts - disproving this claim?
Did you ever hear about the
commonly used method to use a voltage divider for biasing the BJT with a VOLTAGE?
And this applies to all three basic configurations - common emitter (CE) as well as CC and CB.
For CB and CC this is the ONLY method that is used.
More than that - with the aim to make the produced voltage as "stiff" as possible the divider is made as low-resistive as possible.
Didn`t you know that?
Here, "as possible" means "as allowed" with respect to other constraints - in particular with respect to the amplifiers input resistance, which shouldn`t be too low.
Of course, for calculating both resistors, the current IB has to be taken into account - simply because it exists (principle of loaded voltage divider).
However, IB has absolutely no controlling properties. If the base current IB would be only 1% of the current through the voltage divider (or smaller) you even could forget the base current at all for during calculating the corresponding two resistors.