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Mike, just for future information, you don't need to connect any transformer wires together to make a full-wave rectifier with a centre-tapped transformer. Here's an example:-No, it does not have a center tap. The package said black and either yellow for 6v. Yellow and yellow for 12v. But not to connect any of the 3 wires to each other. I've never ran into that before. That's why I used a bridge.
You need to make some circuit changes to do that. This isn't a constant-current circuit, only constant voltage.Might make a couple more in the future as constant current chargers.
You can't do that. It's a dead short across the secondary, and will kill it.I connect the two ends of the windings together then between them and the 'center tap' you get half voltage at full current.
Mike, the dropout voltage, (not usually referred to as 'delta'), is about 2.4V at 2A and 25°C. Allowing for troughs in the input voltage when it's fed by a rectified AC source, about 3V is a good safe minimum to stick to. The dropout voltage is about 2V at 25°C when the current is a little below 1A. All of these values need to be 'de-rated' for higher temperatures.Dorke, when used with solar panels I have observed the 350 still supplying current to 6v batteries with a delta as low as 2 v.
"35 years since... I have forgotten so much and so much has changed."
You're not wrong there. I was out of the field for 10 years, and the combination of what I've forgotten and the advances in the intervening period has left me floundering a bit. Getting there though.Yes we forget a lot(and it is frustrating ,me too).
Nowadays in EE field ,2 years are a generation ,10 years an era...
The other side of the LM350 limit is Vi-Vo>3V.
So if you have another LM350 use them in series to do this:
Use the 12V of the transformer!
12VAC -->retifier+filter cap-->LM350T output set to about at 11V-->LM350T output set to 6V.
important:;
use a full rectifier ( bridge or dual diode) not a single diode!
also use the protection diodes for the LM350s.
If you desire the lowest ripple possible use Cadj=10uF
it will be something so low you can't measure...
On the inputs of the LM350s use a 0.1uF to ground,
very close to the inputs ans very short wires.
Between the two just a 0.1uf (no electrolyte needed).
"Each regulator will drop about 3 volts" ???
Try simulating that.