Sadlercomfort
Ash
Hi Guys,
I'm investigating a faulty infrared remote at work, the remotes seem to be discharging the 9V batteries when not in use.
Now, upon my initial investigation I noticed that the Schottky Diode which protects the circuit from reverse polarity was open circuit. I then confirmed this fault was caused by reverse polarity by using a new remote, which again caused the Schottky Diode to go open circuit.
Now I'm wondering whether the Schottky Diode became 'Resistive' before failing open circuit.. which could explain the discharge rate of the batteries.
I would like to know:
-Is it possible for Diodes to become resistive?
-If so.. Is this the defect im looking for?
-What can cause batteries to discharge quickly when not in use?
Thanks,
Ash
I'm investigating a faulty infrared remote at work, the remotes seem to be discharging the 9V batteries when not in use.
Now, upon my initial investigation I noticed that the Schottky Diode which protects the circuit from reverse polarity was open circuit. I then confirmed this fault was caused by reverse polarity by using a new remote, which again caused the Schottky Diode to go open circuit.
Now I'm wondering whether the Schottky Diode became 'Resistive' before failing open circuit.. which could explain the discharge rate of the batteries.
I would like to know:
-Is it possible for Diodes to become resistive?
-If so.. Is this the defect im looking for?
-What can cause batteries to discharge quickly when not in use?
Thanks,
Ash