You cannot sell a kilowatt unless you specify how long that kilowatt will
last. For example if I was buying a kilowatt from you and you were to keep
the power on for 1 hour, I would get my 1 kWhr. If you gave me 1kW for a
millisecond I would get 0.001kWhrs. You cannot sell electricity in
kilowatts. Kilowatts is only useful for working out maximum demand or
estimating usage/generation if given a time factor. Without the time factor
it is an instantaneous figure and doesn't help much at all.
I did. See my other post in this thread.
Well, there's one error right there. It's not kW/hr/day, it's kWh/
day. Here's the fraction
You are correct. The fraction above is incorrect. The one below is correct.
kilowatts * hours / days
Notice that the time units are in both the denominator and the
numerator, so that they can cancel, yielding a constant. Sot he
answer is in kilowatts. A rate.
Not so sure about this one but basically yes if you take into account the
24:1 difference.
Don't use terms that you don't understand. A rational fraction is one
that can be expressed as M / N, where M and N are integers. It has
nothing to do with units.
Almost right.
A fraction by definition is made up of integers (whole numbers).
e.g. 9 1/2 /2 (9 and a half over 2) is not a valid fraction and never has
been. 18/4 or more correctly 4 1/2 is a valid fraction.
Actually, kilowatts per day is a pretty useful number.
Kilowatts per day? Meaningless unless the load is constant, which it almost
never is, or a time factor is given with it. Kilowatt hours/day is useful,
this tells you your power consumtion for that day. Kilowatts is only useful
in estimating power consumption if the time that the load is on each
day/week/month/year is known. e.g 1kW x 12 hours/day = 12kWhrs/day =
84kWhrs/week = etc. etc.
Look again. Your link says kilowatt hours/day, not kilowatts/day. The result
is in watts and is simply an average load for the day.
Mike, take a long look in the mirror.
I hope this clears up a few things for those other readers that are a bit
confused.
Bruce
Just an average Joe trying to help.
BTW has anyone gotten around to helping the original poster with the info
they asked for about the specs for his 5200 serial comm. port. That would be
helpful.