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PVPowered 5200 serial comm port specs needed

I would like to know the specs, at least correct baud rate, parity, stop
bits for a PVP 5200 unit.

I have a PVM1010 on it and can get the data via Ethernet and internet
but need to know how to get better info from the DB9.

I have tried many baud rates and parity but don't get anything
recognizable.

Thanks for any help on this.

Mike
 
The usual "offend as few people as possible" settings for serial

I almost fell out of my chair when I saw this opening line.
Just_a_fan wants to offend everyone.

He wants to buy and sell KW, and thinks the use of the term kWh, especially
kWh/day, is a sign of a mental defect.

He berates PG&E as being full of idiots because the Time of Use meter
doesn't recognize the change in Daylight Savings Time hours.
 
I have answered my own question.

It is 9600 n 1. It took a while to get it right because the serial port
sniffer I am using really sucks! Brand new and operates like a 100 year
old car. Slow and NONE!

There are two frames. One is an ID frame which is requested each
minute. The other is an operational parameters frame which it gets each
second.

That is aggregated into an average across the minute and sent to its
mother.

Mike

On Mon, 10 Mar 2008 13:39:22 -0700, in alt.solar.photovoltaic
 
On Mon, 10 Mar 2008 21:36:12 +0000 (UTC), in alt.solar.photovoltaic
He wants to buy and sell KW, and thinks the use of the term kWh, especially
kWh/day, is a sign of a mental defect.

IT IS! Try to define it. It is impossible. Do the math. It does not
work!!! Write out the fraction for kW/hr/day and try to make it a
rational fraction. You end up with something completely useless.

If you cannot figure that out for yourself, I feel sorry for you and all
around you.
 
9600 n 1 is it. Right first guess. The biggest problem was the sniffer
that I purchased. It was not cheap but it is not good! It will record
for a while then stop without message or warning.

First laptop was a total failure. Drivers would not install. Second
one at least got me some data to work with. But more failures than
good. I have to call that company again and see what the problem really
is.

So I am on the way. I found out most of the data and am almost ready to
go.

I already have a great monitoring program that collects and presents the
data in various ways and saves up a year's worth for historical
graphing.

Nice but only runs on PVM1010 at this time. If I get more specs, I can
modify it with a different decoder routine and branch out.

PVPowered has a site that collects the data, too, but only two things
captured (kW-minutes and voltage) and only on a 15 minute cycle. Nice
as a backup if I have some kind of outage and cannot collect. I show
each kW-minute and daily kW production.

No, I don't show kW-minute-days since it does not exist.

Mike
 
B

Bruce Harvey

You cannot sell a kilowatt unless you specify how long that kilowatt will
last. For example if I was buying a kilowatt from you and you were to keep
the power on for 1 hour, I would get my 1 kWhr. If you gave me 1kW for a
millisecond I would get 0.001kWhrs. You cannot sell electricity in
kilowatts. Kilowatts is only useful for working out maximum demand or
estimating usage/generation if given a time factor. Without the time factor
it is an instantaneous figure and doesn't help much at all.
I did. See my other post in this thread.


Well, there's one error right there. It's not kW/hr/day, it's kWh/
day. Here's the fraction

You are correct. The fraction above is incorrect. The one below is correct.
kilowatts * hours / days

Notice that the time units are in both the denominator and the
numerator, so that they can cancel, yielding a constant. Sot he
answer is in kilowatts. A rate.

Not so sure about this one but basically yes if you take into account the
24:1 difference.
Don't use terms that you don't understand. A rational fraction is one
that can be expressed as M / N, where M and N are integers. It has
nothing to do with units.

Almost right.
A fraction by definition is made up of integers (whole numbers).
e.g. 9 1/2 /2 (9 and a half over 2) is not a valid fraction and never has
been. 18/4 or more correctly 4 1/2 is a valid fraction.
Actually, kilowatts per day is a pretty useful number.

Kilowatts per day? Meaningless unless the load is constant, which it almost
never is, or a time factor is given with it. Kilowatt hours/day is useful,
this tells you your power consumtion for that day. Kilowatts is only useful
in estimating power consumption if the time that the load is on each
day/week/month/year is known. e.g 1kW x 12 hours/day = 12kWhrs/day =
84kWhrs/week = etc. etc.

Look again. Your link says kilowatt hours/day, not kilowatts/day. The result
is in watts and is simply an average load for the day.
Mike, take a long look in the mirror.

I hope this clears up a few things for those other readers that are a bit
confused.

Bruce
Just an average Joe trying to help.
BTW has anyone gotten around to helping the original poster with the info
they asked for about the specs for his 5200 serial comm. port. That would be
helpful.
 
D

David French

Should be 0.0002777 kWh

There are 3600 seconds in one hour, not 1000, so-

1.0kW * 0.001 second = (1.0kW * 0.001sec * 1/3600hr) kWh.

Mmm - is that the same thing as a watt-second?

Yes, it is one watt-second.

David.
 
D

David French

<snip>
" Should be 0.0002777 kWh. "
</snip>

Ooops - I typed a 'k' by mistake.
It is 0.0002777 Wh., or 0.0000002777 kWh.

Even I'm getting tired of all the decimals now - sheesh!!

David.
 
B

Bruce Harvey

Care to recalculate that? :)

Nick
Oops! In my rush to be a smart ass, I managed to make myself look like a
dumb ass.
1kW for 1 second would be 1kW-second of course or 1kW-hour/3600 or
0.00027777777......kWhrs.
Sorry about that.
I will use a calculator next time.
 
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