Good point. Hmm, what happens if you reverse a Darlington?
If it were a plain BJT, it would immediately be in normal bias as an
inverted transistor...but you'd zener the BE junction, which with a big
bypass on the output would turn it to lava. Check.
If the Darlington were really just two BJTs, then when it inverted the
driver stage would find itself connected from the base to the 'emitter'
of the inverted transistor...which should make it turn off fine, except
that you'd still zener the output stage. Lava again.
Assuming the MPSA14 has a built-in pulldown resistor on the base of the
output device, that would be trying very hard to turn on the inverted
output stage, and there'd still be the BE breakdown. More lava.
So okay, it needs some diodes. If one were to use 1N4005s or the
equivalent, though, their capacitance would be a problem--it's 15 pF,
typical, even at -4V, whereas this is only -1.5V. (It's the low Cce of
the transistor that makes this circuit work so well.)
To protect the CB junction, a diode from output to input would work, as
long as the output bypass cap was at least 10**6 times bigger than the
diode capacitance.
To protect the base, I'd probably put another smaller resistor in series
with the base lead to limit the fault current. If you wanted to use
diodes to protect the base, you could put one diode across each of the
resistors, so the sneak path would be heavily bypassed in the middle.