paul said:
can anybody tell me how to calculate the size of resistor required to drop a
29.4v dc supply rail down to 24.5v?
R = 4.9/I
where R is the resistor size in ohms and I is the current.
After figuring R, use the formula P = I^2R to figure the
wattage that will be dissipated - and then double that figure
to provide a good safety margin for the resistor wattage
rating.
That will give you what you asked for - but not what you need.
Build a regulated supply, using the 29.4 volts as the input.
Use an LM317 (or similar) as pieter indicated, with sufficient
pass transistors/heat sinks to create a regulated supply at the
voltage and current you need.