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Power mesure ac or dc signal

hi,

i've an idea ......but i nedd to know if can work corretly.


I've a TV hall tranducer dor voltage and a hall transducer for current.

In the transducer i put AC sinewawe or cc signal.

after the tranducers i put 2 true rms-to DC converter.

Now,
if a multiple with AD632 i can calculate the power.This shold be
correct fot DC signal.

But with AC signal......the multiplier can give me the real Power?

If a put direcly the outputs of transducer to AD632 (with sine signal)
an at the out i filter with low pass of 10 Hz Fs the power is
correct?The AC sigla has 50 hz frequency.

Any help is welcome.

Ciao
 
C

Chris

hi,

i've an idea ......but i nedd to know if can work corretly.


I've a TV hall tranducer dor voltage and a hall transducer for current.

In the transducer i put AC sinewawe or cc signal.

after the tranducers i put 2 true rms-to DC converter.

Now,
if a multiple with AD632 i can calculate the power.This shold be
correct fot DC signal.

But with AC signal......the multiplier can give me the real Power?

If a put direcly the outputs of transducer to AD632 (with sine signal)
an at the out i filter with low pass of 10 Hz Fs the power is
correct?The AC sigla has 50 hz frequency.

Any help is welcome.

Ciao

Hi. You seem to be pretty close to a good circuit here. A couple of
things:

Hall effect sensors measure current. Are you saying you're using a
hall effect sensor to measure the voltage? I'm not clear on this.

Power _is_ volts times amps. The difference in phase for non-resistive
loads can be a problem, though. Your basic idea is a good way of
solving this. At any instant, the true power is the instantaneous
volts times the instantaneous amps. If you apply to a four-quadrant
multiplier a voltage proportional to the instantaneous load voltage and
a voltage proportional to the instantaneous load current, the
multiplier output voltage will be proportional to the instantaneous
real power being used by the load. If the reactive load is feeding
current back into the line, it will show on the multiplier output at
that instant as a negative voltage corresponding to an instantaneous
negative power. No need for RMS-to_DC converters here, for AC or DC.

Some multiplier-based power meters will use a transformer to measure
the load voltage. That does have a low frequency cutoff, I'm afraid.
But there are other ways to do this, depending on how you're using your
signal. You can just divide down the load voltage, for example. This
can be of value if you're only using an isolated meter or displaying
voltage on a display. You do have to be careful with line potential,
but this should be doable if you're careful. If you consider this, be
careful to limit the maximum voltage while minimizing the signal
distortion. If you're planning on doing this to measure line based
loads, you should definitely use an isolation transformer during
development and testing. Be safe.

The AD632 works with 1% accuracy from 50KHz down to DC (the 10Hz part
has to do with noise). I'm wondering why you need a 10Hz low pass
filter. What do you want to do with the signal? Are you trying to
measure average real power? As long as that's all you're doing, lose
the 10Hz low pass, set your DVM on a DC voltage range higher than the
maximum output voltage (say, the 20V range) and just attach the meter.
You will be delighted.

http://www.analog.com/UploadedFiles/Data_Sheets/130123616AD632_a.pdf

Feel free to post again if you have any questions.

Good luck
Chris
 
Hi Chris,

thanks for you answer!

My system must read the real power that a big Auxiliary converter take
from a hv generator.The converter can use 3000Vcc and 1500V 50 Hz and
1000v 16 2/3 Hz.

So,for monitorig tension and current, with an DC panel, both ac and DC
source generator i convert with AD637(true rms to DC) Ac or DC .And
this part of circuit goes well.
The tension trasducer is an Hall effect ABB transducer wich can take up
to 5000v AC or DC and give 20 mA for end of scale.

Now,the other problem is reading average real power.

I multiple the V and I with AD632 .......but i must integrate.So i
tought to filter the out of multiplexer with an active low pass filter
with a 10 Hz(very low) Fs and read his output on digital panel meter in
DC.
If the supply is DC i think that there aren't poroble also without the
filter........bat when the supply is AC???

You say that without filter the aout of multiplier is the real power
that load take also if is supply with AC?

The value of multiplier should be about 2 or 3 volt max when load takes
max power.

What do you think?


By,

MAX
 
C

Chris

Hi Chris,

thanks for you answer!

My system must read the real power that a big Auxiliary converter take
from a hv generator.The converter can use 3000Vcc and 1500V 50 Hz and
1000v 16 2/3 Hz.

So,for monitorig tension and current, with an DC panel, both ac and DC
source generator i convert with AD637(true rms to DC) Ac or DC .And
this part of circuit goes well.
The tension trasducer is an Hall effect ABB transducer wich can take up
to 5000v AC or DC and give 20 mA for end of scale.

Now,the other problem is reading average real power.

I multiple the V and I with AD632 .......but i must integrate.So i
tought to filter the out of multiplexer with an active low pass filter
with a 10 Hz(very low) Fs and read his output on digital panel meter in
DC.
If the supply is DC i think that there aren't poroble also without the
filter........bat when the supply is AC???

You say that without filter the aout of multiplier is the real power
that load take also if is supply with AC?

The value of multiplier should be about 2 or 3 volt max when load takes
max power.

What do you think?


By,

MAX

Hi, Max. It sounds like you're really on the right track. Considering
the voltages involved, I'm sure you're going the extra step to be safe.

It sounds like you're not positively sure about real power and apparent
power.

Real power is the average of the instantaneous voltage-current product
over a line cycle.
Apparent power is just the product of the rms voltage and rms current.
Period. You're going about this the right way by not just multiplying
the outputs of your RMS-to-DC converters. It sounded like that was
what you were possibly doing on your first post. If you want an analog
representation of real power, you have to directly multiply the direct
outputs of your transducers, and then average that over the line cycle.
Don't believe me -- look it up.

Now you may have some difficulties with the digital panel meter. Most
all of them are based on an ICL-7107 or ICL-7135 IC, which does dual
slope integrating D-to-A conversion. Here's a reference that might
give you an intro:

http://www.intersil.com/data/an/an017.pdf

Now you're going to have some difficulty using a DPM by itself, because
they're usually adjusted to achieve maximum noise rejection at a
particular line frequency. Your 50Hz rejection will be good, but your
16-2/3Hz regection maybe not so much. You're going to have to
carefully evaluate, and make compromises between noise reduction and
response time. Either that, or you may also be able to have one of
these meters custom-modified for the lower frequency. It's just math
and component selection -- the chip can handle it. The 7107/7135 IC is
capable of slower conversion rates, and has inherently great line
frequency reject at that one particular frequency.

But I'm wondering, for example, if it's necessary to have a 10 Hz f(c).
Possibly a lower cutoff frequency might be more useful. After all, no
one is capable of visually absorbing 10 readings per second, anyway.
Of course, since you're talking about a total project accuracy of a
couple of percent, you should remember that an analog meter does the
averaging automatically. You also don't have to worry about power.
Some taut band analog meters with mirrored backing can get you pretty
close, too. But if you use an op amp filter, watch for offset and
drift. Get premium op amps that will stay put.

When doing this project, I would think your biggest difficulty will be
offset and drift in the multiplier itself. This is going to be a
particular problem if your circuitry is in an industrial environment
with major changes in temperature. Five percent accuracy plus annoying
offset is easy. Getting it down below two percent, and getting the
offset at a minimum is going to take some looking at to do well.
Something you may want to look at is periodically doing an offset null
like a low frequency chopper. Many ways to get this better than a
couple of percent accuracy, if that's your need.

It sounds like you've got a genuinely interesting project on your
hands. Take the time to read up on things. I remember doing one of
these years back with an old Motorola analog multiplier. I had a lot
of fun, and learned quite a bit about practical instrumentation tricks
in the process. You've got a much better IC that will try to make you
look good. The old Motorola IC I used needed half a dozen tweaker pots
and seemed like a spirited but rather willful pony that always wanted
to drift off and roll in the grass when it felt like it (sorry, Mr.
Thompson). This is the type of project that can lead you to real
professional growth.

Good luck, and be as safe as you can
Chris
 
Hi Chris!


Now i've configured the AD632 as datasheet for scale factor 1 with vso
to gnd.In this condition i can't trim the offset.
The problem now is that with a signal in input of multiplier below 1
volt the ad give 9 volt!! if i put signal up 1,5 volt it work well.Why?
Is it probably needing offset trimming?

Another thing.When a multiplie the 2 sine wawe the frequency is the
double,and this is correct.So the the line cycle at the out of
multiplier can be 100 hz or 32 Hz.

For having the average of I*V on the cycle is necessary to filter?Yes
the panel meter use the ICL7107.Do you think that if i must filter i
can use the AD797 op amp?
Last question:

if i put directly the out of miltiplier to DPM when i use sine wawe
what i read? The real power?
With the DC i think yes.......but AC??

thanks again.

Ciao,

MAX
 
C

Chris

Hi Chris!


Now i've configured the AD632 as datasheet for scale factor 1 with vso
to gnd.In this condition i can't trim the offset.
The problem now is that with a signal in input of multiplier below 1
volt the ad give 9 volt!! if i put signal up 1,5 volt it work well.Why?
Is it probably needing offset trimming?

Another thing.When a multiplie the 2 sine wawe the frequency is the
double,and this is correct.So the the line cycle at the out of
multiplier can be 100 hz or 32 Hz.

For having the average of I*V on the cycle is necessary to filter?Yes
the panel meter use the ICL7107.Do you think that if i must filter i
can use the AD797 op amp?
Last question:

if i put directly the out of miltiplier to DPM when i use sine wawe
what i read? The real power?
With the DC i think yes.......but AC??

thanks again.

Ciao,

MAX

Hi, Max. This IC is super easy to use for your application. If you're
using the Fig. 6 circuit, you have to remember to tie off the unused
inputs. The X and Y inputs are differential. So, if you're just
multiplying two voltages, ground X2 and Y2, then try again. If this
doesn't work, check your wiring. It's a 14-pin IC, there are 4 NCs,
two power and 5 grounded. All you've got is X1 * Y1 = OUT. Hooked up
this way, there's no wiggle room at all -- you'll have a DC offset, but
it's gotta work, or the chip was smoked (ouch -- these are expensive).
This is a basic cut here. This is so simple, if you have any
electronics experience at all, you have to get this. Check your
wiring, or try a new chip. I'll bet you've got it hooked up wrong.

I think it's a mistake to use unity scale factor, because that will
limit the input amplitude of your signals. You should look toward the
circuit in Fig. 5 as giving you better accuracy. For instance, in Fig.
6, your input signals would be limited to a product of 10V^2. That
would mean you'd have to scale each of your inputs smaller because of
power supply limitations. The chip is made to a scale factor of 10,
which will mean your input signals can be a product of 100V^2. This
will provide more accuracy.

As mentioned before, to get real power, you have to average the
instantaneous product. You use filtering to get the average. I would
look at using an active low pass filter (using a fast low offset op amp
to minimize error) between the multiplier output and your DPM. As
mentioned in a prior post, I'd try to make the filter f(c) as low as
possible to get the DPM input as close to pure DC as possible. Do you
need help with this?

You might want to go back and refresh your knowledge. Let's say you
have a purely reactive load -- say you're driving a capacitor with AC.
There will be reactive power, but no real power. If you look at the
output of your multiplier, you will see a waveform that goes + and -.
However, the average voltage will be zero. The DC component of the AC
waveform at the multiplier output will be zero. That means that if you
use a perfect low pass filter, its output will be 0.000V.

Ideally, a DC meter reading this AC waveform from the multiplier output
will see no DC, and will read 0.00V. However, unless the signal
happens to be at the one particular frequency (or a multiple of that
frequency) that the -7107 circuit was optimized to reject, you'll
probably see the reading of the DPM move around -- you won't get a
stable signal.
From your post, it kind of seems like you might be in a little over
your head. Usually that's not a problem (after all, this is a
newbie/hobbyist newsgroup), but when you're dealing with several KV,
that can be fatal. Do you have any experience in electronics? More
particularly, have you worked with high voltage before? I'd really
like to know before giving you a hand here. Haven't gotten anybody
killed yet, and it's too late to start.

If you're not familiar with the high voltage end of things, I'd really
recommend you stop immediately, and give your project to someone who
can work confidently with HV.

Chris
 
Hi Chris,

no problem with HV,because i work every day with Hv.Normally i use
Tektronix Hv probe(X1000).

Now,because i want to create a test bench that doesn't use Hv probe and
not Aron insertion wattmeter,my idea was use this analog multiplier.

For unity scale factor,i thinked to use this configuration because X1
can reach at max 4 volt and Y1 300mV.But if you say that with 10 scale
factor is more accurate i think that i'll go to use 5 figure in
datasheet of AD632.

The Ad632 works well,but if i left the X1 and Y1(X2 and Y2 are
grounded) wituout signal at the out i've 9 volt.When i charge the 2
input the multiplier works ok.

I've used a active low filter of 5 order with 3 AD797.

If i put into AD632 2 signal of 2 Vrms at the output i've 4,1 volt.When
i filter i've 4,8 volt DC plus 100mV AC.

Is it correct?

I 'testing the circuit in low power and lov tension,with a Fonction
generator wich can give me 2 volt RMS.I put this 2 volt Rms in X1 and
X1 input of miltiplier.The output is 4,1 volt.But why after the filter
the dc signal riseto 4,8 Volt?Is it probably related with average
value?

Question: what is the ok reading after the filter(10 hz Fc) when i
multiple 2 volt rms in X1 and X2???


Thanks,

ciao,

MAx
 
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