I'm building a circuit with an active load which happens to be a constant current sink.
One desired factor is a high impedance, and since it's for an audio application I really want it to be flat over audio frequencies.
The results first (please excuse the mobile phone images.
At 130Hz:
The input signal is 2V/div and the smaller output signal is 2mV/div.
The input signal represents the change in voltage seen by the current sink. 8V peak to peak represents the largest voltage swing expected. The supply rail is 18V.
The output signal is the voltage across a 100 ohm resistor, and is a measure of the change in current.
Before the math. Let's look at higher frequencies:
1.3kHz
13kHz:
And finally at 130kHz:
As you can see, things are starting to degrade at 130kHz, but I can't hear frequencies that high .
I'm going to call that output voltage 1.5mV. Across 100 ohms that is 15uA.
If a change of voltage of 8V produces a change in current of 15uA, then the impedance is in excess of 500k.
Given that it's a very simple current sink, I'm happy with that performance.
I'll draw the circuit in a moment
One desired factor is a high impedance, and since it's for an audio application I really want it to be flat over audio frequencies.
The results first (please excuse the mobile phone images.
At 130Hz:
The input signal is 2V/div and the smaller output signal is 2mV/div.
The input signal represents the change in voltage seen by the current sink. 8V peak to peak represents the largest voltage swing expected. The supply rail is 18V.
The output signal is the voltage across a 100 ohm resistor, and is a measure of the change in current.
Before the math. Let's look at higher frequencies:
1.3kHz
13kHz:
And finally at 130kHz:
As you can see, things are starting to degrade at 130kHz, but I can't hear frequencies that high .
I'm going to call that output voltage 1.5mV. Across 100 ohms that is 15uA.
If a change of voltage of 8V produces a change in current of 15uA, then the impedance is in excess of 500k.
Given that it's a very simple current sink, I'm happy with that performance.
I'll draw the circuit in a moment