anyone know how to design a phase shifter circuit with standard
components?
input signal: 6.1v ac rms, 488hz
phase shift: 23 ±5 deg lead
output signal: must be capable of driving a DDC DRC-10520 (Ref
signal).
±15V on the board
any advice/books/links that might aid this design?
Seems like other posters so far haven't quite groked what a DRC-10520
is. You need to drive the differential reference input with a
sinewave (not digital) at 3.4V RMS, and the input impedance is
guaranteed within 0.5% of 26 kohms. If your input 6.1V is isolated
(not ground referenced), it should be easy to use series capacitors
and resistors to scale and phase shift. Phil Hobbs' posting gives
you the basic info you need for the phase shift part...you just need
to understand how much attenuation there is in the high pass filter so
you know the voltage out of it, and then pick the load resistance such
that the added resistors and the internal DRC-10520 resistance form a
voltage divider to get you the rest of the way to 3.4 volts.
If your 6.1V is ground referenced, then I'm unsure whether you will be
able to use that directly or not. The DRC-10520 data sheet is very
vague on the common mode range of the reference input, and whether it
must be driven differentially or if instead RL may be grounded. I'd
call DDC about that one, to find out. If it can be grounded, then you
can just use a single series RC from your 6.1V to get the phase shift
and the attenuation. But DDC's data sheet for this part only shows
the reference being driven from an isolated transformer winding, so
it's not really clear how you're supposed to drive it single-ended.
It's also unclear to me just what they mean by listing different
single-ended and differential reference input impedances; perhaps you
can drive it single-ended with RL floating. Again, get ahold of DDC
and ask them! They should be happy to provide you with some
applications info about the part. It's to their advantage to have you
use the part successfully.
Cheers,
Tom