The battery charger for an 18 volt portable drill/driver has burned out and the company is no longer in business to provide a replacement. The circuit charges an 18 volt NiCad battery which is made up of 15 1.2 volt cells each rated at 1200mAH. The original AC power supply, which also burned out, is rated at 120v AC 60Hz input and 18v DC 400mA output.
I attached a photo with a crude diagram along with the actual circuit board. I need help identifying the suspected fried circuit component (the large gray one with all of the black behind it), determining its proper value, and finding a replacement.
Out of circuit, the suspected gray component measures 2.6 ohms (assuming it is a resistor). Honestly, I do not know enough about electronics to understand how the circuit works. Obviously, the LED is supposed to light when a battery is placed in the charger. However, I have never seen the LED go off when a battery is fully charged.
The diode appears to be OK, when tested with an ohm meter, and the small resistor measures closer to 90 ohms than what the 100 ohm bands indicate. It is a simple circuit but I do not know how to make it work properly again.
Thank you for any insights.
I attached a photo with a crude diagram along with the actual circuit board. I need help identifying the suspected fried circuit component (the large gray one with all of the black behind it), determining its proper value, and finding a replacement.
Out of circuit, the suspected gray component measures 2.6 ohms (assuming it is a resistor). Honestly, I do not know enough about electronics to understand how the circuit works. Obviously, the LED is supposed to light when a battery is placed in the charger. However, I have never seen the LED go off when a battery is fully charged.
The diode appears to be OK, when tested with an ohm meter, and the small resistor measures closer to 90 ohms than what the 100 ohm bands indicate. It is a simple circuit but I do not know how to make it work properly again.
Thank you for any insights.