I understand how the LM78XX works, but I'm having trouble with the current booster. The data sheet says that even at half rated current the LMXX needs a heat sink. That's OK, but I would rather avoid it.
So they have a diagram for a High Current Add On. (Question 1. Will this keep the LM78XX from getting hot if it turns on at, say, .25 max I?)
I have a good picture, but can't figure out how to post it. Anyway, there are only two components in the High Current part of the circuit.
1. A resistor which is connected to the input on one end, and to the junction between the input to the LM78XX and the filter capacitor which is connected to the LN78XX input and ground.
2. A transistor connected between the input to the circuit and the output from the LM78XX. This transistor has the Emitter connected to the circuit input, Collector connected to the output of the circuit, and the Base connected to the input pin of the LM78XX.
Two formula are given.
1. R1 = Vbeq1 / (Ireg - Iq1) / Bq1.
What is Vbeq1? Base to Emitter voltage of Q1?
2, I assume Iq1 = current out of the transistor.
3. Is Bq1 = voltage on the base of Q1?
Other formula; Io = Ireg + Bq1 * (Ireg - Vbeq1 / R1).
I would like to build one of these, but am not sure enough of what values are being used.
So they have a diagram for a High Current Add On. (Question 1. Will this keep the LM78XX from getting hot if it turns on at, say, .25 max I?)
I have a good picture, but can't figure out how to post it. Anyway, there are only two components in the High Current part of the circuit.
1. A resistor which is connected to the input on one end, and to the junction between the input to the LM78XX and the filter capacitor which is connected to the LN78XX input and ground.
2. A transistor connected between the input to the circuit and the output from the LM78XX. This transistor has the Emitter connected to the circuit input, Collector connected to the output of the circuit, and the Base connected to the input pin of the LM78XX.
Two formula are given.
1. R1 = Vbeq1 / (Ireg - Iq1) / Bq1.
What is Vbeq1? Base to Emitter voltage of Q1?
2, I assume Iq1 = current out of the transistor.
3. Is Bq1 = voltage on the base of Q1?
Other formula; Io = Ireg + Bq1 * (Ireg - Vbeq1 / R1).
I would like to build one of these, but am not sure enough of what values are being used.