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Need help on the working of this LED inverter circuit (joule thief)

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:confused::confused::confused::confused::confused::confused::confused::confused:

when i used gauge 33 than output volt-4.22/0.12-0.11ma with 11ohm resistance.

how to get more mA output? use capacitor?
 
You might want to take a look here:

http://en.wikipedia.org/wiki/Joule_thief

http://en.wikipedia.org/wiki/Dot_convention

http://en.wikipedia.org/wiki/First_law_of_thermodynamics

You have a finite amount of energy in the two battery cells. The joule thief concept works by maintaining a constant output voltage.

Typical AA battery cells contain 2700mAh (milliamp hours) of electricity. This means you could drain 2.7 amps out of a single cell for one hour, or 5.4 amps out of a single cell for half an hour. Realistically, the current draw will be limited by the physics of the cell.
 
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