Because Q3 is off, the +ve end of C1 is effectively connected to ground via the 33ohm resistor. As soon as Q1 turns off, C1 begins to charge through the 330K resistor and the voltage at the base of Q2 rises toward 0.6V
Please explain this too me. The schematic shows an electrolytic capacitor. I don't understand how the capacitor can charge when the polarity is backwards???