I believe the beam angle for lights can be calculated by the following formula -
α = 2 arcCos ( 1 - Lm ÷ ( 2 π Cd ) )
where,
α = beam angle in degrees; and where beam intensity falls off to 50% of maximum (apparently)
Lm = luminous flux in lumens
Cd = luminous intensity in candelas
The difficulty I have is understanding where the "50%" comes in to it?
I thought the above formula calculates the TOTAL beam angle where the beam intensity falls off to 0 or near 0!?
First question :
Where does this 50% figure come from? Is it just some random figure? Or is it calculated from somewhere?
The "field angle" of light beams is apparently the light beam angle where the beam intensity falls off to 10% of maximum. This field angle is greater than the beam angle.
Second question :
What is the formula for calculating the field angle?
Thank you for any helpful replies!
α = 2 arcCos ( 1 - Lm ÷ ( 2 π Cd ) )
where,
α = beam angle in degrees; and where beam intensity falls off to 50% of maximum (apparently)
Lm = luminous flux in lumens
Cd = luminous intensity in candelas
The difficulty I have is understanding where the "50%" comes in to it?
I thought the above formula calculates the TOTAL beam angle where the beam intensity falls off to 0 or near 0!?
First question :
Where does this 50% figure come from? Is it just some random figure? Or is it calculated from somewhere?
The "field angle" of light beams is apparently the light beam angle where the beam intensity falls off to 10% of maximum. This field angle is greater than the beam angle.
Second question :
What is the formula for calculating the field angle?
Thank you for any helpful replies!