I have a situation in a piece of equipment where power to a necessary IR LED has malfunctioned. Every other function on this equipment works fine, just for some reason it stopped powering the LED. The only DC power available inside the unit is 24 V straight off the PS.
Using a linear circuit, I have confirmed that powering the LED by bypassing the main board works, unfortunately (obviously) it puts off a lot of heat. I'd like to put a small board inside the unit, with a switching supply to power just the IR LED.
After some poking around, I've determined this circuit will work, and I can assemble for less that $1.50. This is pretty much straight from the LM2576 data sheet, just with my load attached. Data sheet also calls for a much larger inductor, as the regulator is rated at 3A, but I'm only going to be using ~80mA. So I'm planning on using an EC36-101K, which is rated for about 275mA.
Is there a better way to do this, or anything wrong with doing it this way?
Using a linear circuit, I have confirmed that powering the LED by bypassing the main board works, unfortunately (obviously) it puts off a lot of heat. I'd like to put a small board inside the unit, with a switching supply to power just the IR LED.
After some poking around, I've determined this circuit will work, and I can assemble for less that $1.50. This is pretty much straight from the LM2576 data sheet, just with my load attached. Data sheet also calls for a much larger inductor, as the regulator is rated at 3A, but I'm only going to be using ~80mA. So I'm planning on using an EC36-101K, which is rated for about 275mA.
Is there a better way to do this, or anything wrong with doing it this way?