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Inductance of 820 ohm 10w wirewound

P

Phil Allison

"Trevor Wilson"
**I said: INDUCTIVE REACTANCE.


**I've done so on many occasions. Though, I hasten to add, not 820 Ohm
resistors.

** Weeeeellllll - that is what I am asking you to try !!!
Usually, much lower value resistors.

** That is the whole point.

The nature of the "coil" is much the same over a wide range of resistance
values.

As is the turn to turn capacitance.
The principle is the same however.

** No it isn't.

I don't see the point in trying to measure inductance directly. As you
have already stated, the resistance value will completely swap the
inductive reactance value. With rudimentary test equipment, it is simple
enough to measure the total reactance and perform the appropriate maths to
calculate inductance.

** You have not tried to do it and are still making silly assumptions.

Read my other posts in this thread.


..... Phil
 
P

Phil Allison

"Trevor Wilson"
All you need to do is:

Measure the resistance.
Measure the total reactance at (say) 100kHz).

** That second job is not possible.

The Z value will be exactly the same as the resistance.

Try 100MHz instead and then see how a few pF of strays ruins the outcome.



..... Phil
 
P

Phil Allison

"StrandElectric"
Oh dear, back to type. That was a very mild comment from me hardly
requiring such an extreme put down!

** Listen fuckhead.

**YOU** will not say what you are up to and the same time you BLAME me for
not knowing.

How fucking CRAZY is that ?????

Bet anything what you are doing with that 820 ohm resistor is 100% nuts.
---------------------------------------------------------------------------------
No, there's much I don't know but I know that, and don't mind asking for
opinions,

** Then like most fuckwits on usenet - you PICK the one YOU like the best
and ignore the correct one or ones.

That is both extradinarily stupid and very bad mannered.




..... Phil
 
S

StrandElectric

Trevor Wilson said:
**No. You are simply measuring the inductive reactance. All you require is
a signal source, a high freqency millivoltmeter, a known non-inductive
resistor (or resistors) and a pocket calculator.

You are over-thinking the whole thing. As Phil has already stated, trying
to measure inductance, with a resistor of such a value is fraught with
difficulty.

Yes, understood. Certainly this ancient brain now gets it that R swamps the
L and the C. Unfortunately (because I had much to learn from him) Phil's
nasty childish ways and foul language have now caused me to block him, so I
won't see any of his wisdom.
 
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