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how to reduce the current without changing voltage for charging a 9 v battery??

I have some rechargeable ni-mh 9v batteries (all 200mah) laying around and a 9v adapter with current output of 210ma... I know that 9 v batteries require 1/10th of its capacity to be charged (ie 20ma)...So ,is there a way to reduce the current output without reducing the voltage (maybe with some kind of resistors in series) so that i can charge these batteries safely??

thanks in advance
 

(*steve*)

¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥd
Moderator
What is the open circuit voltage of your 9V adapter?

What voltage is marked on those rechargeable batteries? 8.4V?

You can charge those batteries with just a resistor to limit current but you risk damaging them.
 
What is the open circuit voltage of your 9V adapter?

What voltage is marked on those rechargeable batteries? 8.4V?

You can charge those batteries with just a resistor to limit current but you risk damaging them.
It is about 9.2 to 9.5 v in open circuit

Only 9v is written on the body ...in some it is written "standard charge: 15hrs at 16ma"

Thanks for the reply
 

(*steve*)

¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥd
Moderator
Try a 68 ohm resistor and measure the current through the resistor AND the voltage across the battery (do you have 2 multimeters?).

Alternatively, measure the voltage across the battery and then across the resistor and use ohms law to determine the current.

Monitor this and let me know what the voltage across the battery and the current into it are after about an hour.

If the battery gets hot, stop charging it immediately.
 
Try a 68 ohm resistor and measure the current through the resistor AND the voltage across the battery (do you have 2 multimeters?).

Alternatively, measure the voltage across the battery and then across the resistor and use ohms law to determine the current.

Monitor this and let me know what the voltage across the battery and the current into it are after about an hour.

If the battery gets hot, stop charging it immediately.
Thanks for the reply :) I'll try that...cause I don't have the 68 ohm resistor now. And I have only one multimeter.... BTW I have tried to make a circuit by myself on paper assuming that the internal resistance of the battery will be 1ohm to 2ohm
Will this work?
Here is the pic of the circuit
 

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Do not use the circuit you have shown, you will discharge whatever is in the battery and kill the power supply.
Do what (*steve*) says.

I suggest that you learn the difference between voltage and current.
 

(*steve*)

¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥd
Moderator
Yeah do what I said and measure a across the resistor with your multimeter on a voltage setting.
 
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