Hi Guys. So I have a project (too wacky to describe in this space) 
that i need help with.
Part of it is a hacked into portable speaker system... one those jambox type look alikes, that is charged by usb and plays for about 8 hours on battery. For my wacky project i have it embedded in a case where i can't get at it easily and just want to leave it on main power USB the whole time (without a battery even). Problem is when I switch off the main power for too long, the speaker's internal battery goes low and then the thing starts beeping like crazy.
I *thought* that the simplest thing would be to unplug its battery's 2 prong molex type connector and run it like that (off USB power). When USB 5v is present, it should work (i thought wrongly), and when it's not, it's good and off and battery dead, and therefore no chance of incessant beeping.
BUT it doesn't work that way does it. I believe the USB power must only be there to charge the little batteries. (via the same 2 prong connector), but me unplugging the battery side of that circuit disables the whole freakin thing. so obviously i can't leave that 2 prong connector unpluged.
SO... the question: in order to close the circuit i need to plug it back into the battery connector and i don't want to. Which leads me to think: i should short the connector. But with what? a wire? a resister (value?) or a transistor?
This is low voltage stuff guys, and LOW value, no danger here.
so I am looking for simple macgyver hack to try, not etching a circuit or flashing new firmware if you follow me? just a kind of: if we were stuck on an island, what and that was the way to radio home, and there was no battery but there was a usb outlet on this island then what would you short that battery connector with? resistor? wire? or transistor? and if so what value should i try.
Thanks
Tom.
that i need help with. Part of it is a hacked into portable speaker system... one those jambox type look alikes, that is charged by usb and plays for about 8 hours on battery. For my wacky project i have it embedded in a case where i can't get at it easily and just want to leave it on main power USB the whole time (without a battery even). Problem is when I switch off the main power for too long, the speaker's internal battery goes low and then the thing starts beeping like crazy.
I *thought* that the simplest thing would be to unplug its battery's 2 prong molex type connector and run it like that (off USB power). When USB 5v is present, it should work (i thought wrongly), and when it's not, it's good and off and battery dead, and therefore no chance of incessant beeping.
BUT it doesn't work that way does it. I believe the USB power must only be there to charge the little batteries. (via the same 2 prong connector), but me unplugging the battery side of that circuit disables the whole freakin thing. so obviously i can't leave that 2 prong connector unpluged.
SO... the question: in order to close the circuit i need to plug it back into the battery connector and i don't want to. Which leads me to think: i should short the connector. But with what? a wire? a resister (value?) or a transistor?
This is low voltage stuff guys, and LOW value, no danger here.
so I am looking for simple macgyver hack to try, not etching a circuit or flashing new firmware if you follow me? just a kind of: if we were stuck on an island, what and that was the way to radio home, and there was no battery but there was a usb outlet on this island
then what would you short that battery connector with? resistor? wire? or transistor? and if so what value should i try. Thanks
Tom.
