Hi Group, This issue is lengthy and detailed. If you read it all, I will be very very surprised. If you can help me, I will be excessively grateful. Grab a cup of coffee and thank you in advance.
I have a 1973 Harley Davidson Z90. These small motorcycles were made by the Italian company Aermacchi in the years when Harley was owned by AMF (late 60's into the 80's). They are an all Italian unit with a Harley emblem on them.
One day when I was about 15, walking home from school in 1985 I found the bike on a trash pile in a neighbors yard and asked if I could have it. I pushed it home and after about 30 years have got it running and its fun but I myself am much bigger now :0
My question is in regard to the voltage regulator. It is working as far as it charges the battery at about 14V in a high rev of the engine, but the aspect of the regulator which is to *cause a charge indicator light to come on whenever charging is less than battery voltage* does not work.
I have been obcessing over this for a couple weeks. There aren't many folks left who apparently are knowledgeable about the electrical portion- at least enough to say "Just change the regulator". But I have decided I want to at least know which component of the regulator is bad before I give up and buy another one (If I can find one).
Heres where most folks eyes start to glaze over. Mine would too if I wasn't so obcesed with this.
The bike is a 12VDC. The 'charge light' is a small bulb located by the speedometer, isolated from ground with 2 wires going to it. One wire (The positive wire) comes from one pole on the coil which is fed (+) when the ignition switch is turned on. The ground for the other lead to the bulb is supposed to come from the terminal "S" on the voltage regulator. When the engine is *not* running and ignition switch on, the regulator is supposed to allow ground to flow to the charge light causing it to light up- in effect letting the operator know that there is no charging going on and to show the bulb is not burnt out.
When the bike is started up, the power (+) from the alternator flows into the regulator and should flow through the S terminal to the 'charge bulb' and the bulb should go out.
So to my problem and my question. With ignition switch on and engine not running, I am not getting any (-) at the S terminal of my voltage regulator therefore not lighting my charge bulb. The bulb is good and the ground connections in the electrical system are clean and free of oxidation and the 'charge bulb' is insulated from ground (and will light if checked manually with test probes).
Question is, from looking at the schematic diagram I shared of the regulator itself, can you determine where and how (-) is supposed to get to the S terminal? Also where is the ground origination to S from? Frame? Generator?
In the manual which I supplied a couple pages, there are 9 tests to test the regulator. I tested mine multiple times and it passed every time with flying colors. I notice that there is a resistor associated with the S terminal(please see images of resistor). The funny thing about this resistor is that from my testing with a test light, although it passed the test , it seems like it only lets current flow through one way and not the other. but be that as in may, I dont know if its designed that way or possibly defective. The resistor appears to have "G.B.C Italiana 68 Ohms 1373"
The regulator is #4 on the diagram and the charge bulb is #17. The regulator has 4 inputs. 'N' for one of the 2 wires coming from the alternator, 'S' for the charge bulb, another 'N' for the second alternator wire, and +B for the battery.
If it is the resistor that is the issue
, I would like to locate a substitute and fix my regulator.
![Screenshot_2019-08-15-15-45-11-1-1[1].png Screenshot_2019-08-15-15-45-11-1-1[1].png](https://makerv2.webteractive.co/forums/data/attachments/44/44367-a9ae43387c02fc264cbe0a2134e742b2.jpg)
I have a 1973 Harley Davidson Z90. These small motorcycles were made by the Italian company Aermacchi in the years when Harley was owned by AMF (late 60's into the 80's). They are an all Italian unit with a Harley emblem on them.
One day when I was about 15, walking home from school in 1985 I found the bike on a trash pile in a neighbors yard and asked if I could have it. I pushed it home and after about 30 years have got it running and its fun but I myself am much bigger now :0
My question is in regard to the voltage regulator. It is working as far as it charges the battery at about 14V in a high rev of the engine, but the aspect of the regulator which is to *cause a charge indicator light to come on whenever charging is less than battery voltage* does not work.
I have been obcessing over this for a couple weeks. There aren't many folks left who apparently are knowledgeable about the electrical portion- at least enough to say "Just change the regulator". But I have decided I want to at least know which component of the regulator is bad before I give up and buy another one (If I can find one).
Heres where most folks eyes start to glaze over. Mine would too if I wasn't so obcesed with this.
The bike is a 12VDC. The 'charge light' is a small bulb located by the speedometer, isolated from ground with 2 wires going to it. One wire (The positive wire) comes from one pole on the coil which is fed (+) when the ignition switch is turned on. The ground for the other lead to the bulb is supposed to come from the terminal "S" on the voltage regulator. When the engine is *not* running and ignition switch on, the regulator is supposed to allow ground to flow to the charge light causing it to light up- in effect letting the operator know that there is no charging going on and to show the bulb is not burnt out.
When the bike is started up, the power (+) from the alternator flows into the regulator and should flow through the S terminal to the 'charge bulb' and the bulb should go out.
So to my problem and my question. With ignition switch on and engine not running, I am not getting any (-) at the S terminal of my voltage regulator therefore not lighting my charge bulb. The bulb is good and the ground connections in the electrical system are clean and free of oxidation and the 'charge bulb' is insulated from ground (and will light if checked manually with test probes).
Question is, from looking at the schematic diagram I shared of the regulator itself, can you determine where and how (-) is supposed to get to the S terminal? Also where is the ground origination to S from? Frame? Generator?
In the manual which I supplied a couple pages, there are 9 tests to test the regulator. I tested mine multiple times and it passed every time with flying colors. I notice that there is a resistor associated with the S terminal(please see images of resistor). The funny thing about this resistor is that from my testing with a test light, although it passed the test , it seems like it only lets current flow through one way and not the other. but be that as in may, I dont know if its designed that way or possibly defective. The resistor appears to have "G.B.C Italiana 68 Ohms 1373"
The regulator is #4 on the diagram and the charge bulb is #17. The regulator has 4 inputs. 'N' for one of the 2 wires coming from the alternator, 'S' for the charge bulb, another 'N' for the second alternator wire, and +B for the battery.
If it is the resistor that is the issue
![Screenshot_2019-08-15-15-45-16[1].png Screenshot_2019-08-15-15-45-16[1].png](https://makerv2.webteractive.co/forums/data/attachments/44/44368-6135418eb932cc9814a43bf27bea8795.jpg)
![Screenshot_2019-08-15-15-44-46[1].png Screenshot_2019-08-15-15-44-46[1].png](https://makerv2.webteractive.co/forums/data/attachments/44/44366-0192da5a6fcc1cb2b8015354a2699f1c.jpg)
![Screenshot_2019-08-15-15-45-11-1-1[1].png Screenshot_2019-08-15-15-45-11-1-1[1].png](https://makerv2.webteractive.co/forums/data/attachments/44/44367-a9ae43387c02fc264cbe0a2134e742b2.jpg)
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