found the parralim...
I DEDUCE----

The resistor 474k bridges the circuit between the two transistors.(the parralim)
The 474k resistor bridges the
collector of the wah circuit transistor, to the
base of the tone/volume circuit transistor
Pin J to the induction coil(500) to everything on the board
Pin E is the negative side of the circuit and is
emitted from the vol/tone transistor.
Pin F is capped and resisted and barred to the fuse block contacting the
collector on the tone/vol transistor.

MY CONNECTIONS_________________________________________________________

Pin D does not run through the induction coil, so it must be the +wah
output from the pot
Pin J must be the instrument input
Pin E must be the amp output
Pin F must be the tone/vol output

or J is the tone/vol input and F is the instrument input

9v power through a [switch(doesn't exist...yet)], to the fuse block at B and F

DO YOU THINK THIS WILL WORK?

The two 1249 tropical fish caps, are hard wired(barred) to the fuse block on either side, one parallel(on the wah circuit) and one in series(on the tone/vol circuit). these two fish must be the 9v filters.
If I don't switch the 9v, which fires the transistors, the circuit passes the signal through the 5way wah selector, and through the tone/vol circuit, and out pin F
Each of the 4 pins(K,L,M,N) attach to the 5way for increasing singularity wah control.
ps. the pedal will work without the 9v, but there won't be an amplification, or tone/vol controls!!!! how about that! a double rectified busthead for everybody!
