E
Eeyore
Jan said:Is the current not also limited by beta x the current drive?
The drive current (bottom transistor) is 0.7 / 110 = 0.6mA.
How did you get that ?
Looks more like 7mA to me !
The beta of the MJE-171 is perhaps about 50, so the I max is 30mA.
At half supply 24V makes .03 x 24 = 720mW in the pulldown.
Pullup will be about the same.
Revise your calculations.
Graham