Calculate Current, Power, EMS..

[Laplace]

If you would like to use standard methods, then first choose the most reasonable ground point, i.e. node 'C'. There is no need to complicate the problem by converting circuit components (R) into equivalent conductance (G). Every complication is a new opportunity to make a conceptual or substitution mistake. Write the node equations with the nodes and branches clearly identified and segregated. My method is to begin every term in the node equation with that node voltage, subtract from it the adjacent node voltage and divide by the branch resistance to the adjacent node, repeat for all adjacent nodes and set the sum of terms equal to zero. Do this and you will get the equations I solved in #34. This is a mainstream approach, not the phantom reference explanation which I pursued as just an interesting aside.

 

[evol_w10lv]

Thank you very much for helping. Acually task is solved. I calculated power power balance by my selfe. I respect your helpful attitude.
And if I have other tasks and lack of understanding, I will certainly ask for your help.

 

[The Electrician]

Make the changes shown in red:

Yes, I would like to see standard methods. For now it is too complicated to use inovative solutions.

I calculated equations:
-Va*(G4+G03+G3+G2+G02) + Vc*(G03+G3+G2+G02) + Vb*G4 = -E3*(G03+G3) + E2*(G2+G02)
-Vc*(G5+G02+G2+G03+G3+G6) + Vb*G6 + Va*(G02+G2+G03+G3) =E3*(G03+G3) -E2*(G02+G2)
-Vb*(G4+G6+G01+G1) + Va*G4 + Vc*G6 = - E1*(G01+G1)

And you should get the result in red:

Va = 0.195342, 17.1043257
Vb = 1.36132, 25.2010178
Vc = 18.4131 18.498728

If you put your voltmeter back the way it was in the first post of this thread, then Vb will be the voltage it will read.