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audio amplifiers: +/- X VDC vs 0-X VDC

M

Michael A. Terrell

Eeyore said:
What a load of drivel.

Don't you ever feel embarassed writing such junk ?

Graham


Do you?


--
Service to my country? Been there, Done that, and I've got my DD214 to
prove it.
Member of DAV #85.

Michael A. Terrell
Central Florida
 
A

Al in Dallas

To invert a signal, you run it through an inverter, To phase shift it, you
run it through some sort of phase shift network; this will be frequency-
sensitive, depending on the frequency and the parameters of your phase
shifter.

And anyone who tells you that an inversion is the same as a 180 degree
phase shift just wasn't paying attention in class that day.

Admittedly, with a sine wave, they LOOK exactly the same; this is
probably the confusion factor for those who don't know the difference
yet.

I think you've hit the nail on the head.
 
E

Eeyore

Jamie said:
You're such a smuck.

You must of been a real prize in your day.

You mean "have been".

You can't even write using the English language competently.

Graham
 
M

Michael A. Terrell

Eeyore said:
I'd certainly feel embarrased if I'd been responsible for writing such idiotic
gobbledegook.


So, you never read what you post?

--
Service to my country? Been there, Done that, and I've got my DD214 to
prove it.
Member of DAV #85.

Michael A. Terrell
Central Florida
 
N

Nobody

I'm just confuse about some basics here. can the 2 sinusoidal waves
that is 180 degrees out of phase with each other be said as inverted?

Yes, as sin(x+180°) = -sin(x)
and, for waveforms other than sinusoidal shape is not necessarily
inverted when they are 180 degrees out of phase?

Correct.

More genrally, for waveforms which contain only odd harmonics (e.g. sine,
square, triangle), inversion is the same as a 180-degree phase shift. If
there are any even harmonics (e.g. a sawtooth wave, or anything with a DC
component), then they aren't the same.
 
J

John Fields

Ignorant sap sucker.

Go back and count your marbles, I think you've
lost some.

---
Once in a while Graham is right, and this is one of those rare
occasions. :)

A "coupling" capacitor is used to connect (couple) the output of one
stage with a quiescent DC different from that of the input of the
next stage by using the dielectric of the capacitor to allow both
stages to float into AC commonality with each other while
disregarding their DC differences.
 
J

John Fields

Yes, that is true, It's also termed Decoupling capacitor because of
the interaction of what it's used in.

---
Sorry, no.

A "decoupling" capacitor is used to isolate portions of circuits
from each other. That is, to destroy the connection between them.

Notably, decoupling capacitors are used as local reservoirs of
electrical energy which will continue to feed a load when another
load causes the supply voltage to glitch.
---
Coupling a circuit via a capacitor is just that, coupling. how ever,
using a CAPACITOR to isolate DC voltage (which is where the original
contents of this started) is termed as Decoupling capacitor which is
more to describe in what it's doing and not what it is.

---
Sorry, no.

Decoupling capacitors are used to isolate (decouple) circuit
elements from changes in their supply voltages, whatever the cause,
while coupling capacitors are used to pass AC signals between stages
with different quiescent DC outputs and inputs.
---
Any one that has really been working in the field knows this how ever,
I find those that just sit there arm chair wise and recite text book
literature and proclaim to be experts are just ignorant to say the least.

Graham, or is it Mr. HAM? the little snake in the grass.

---
That's not fair.

You're trying to impugn Graham with your ignorant "philosophy", (but
not technically) not because _he_ was technically wrong, but because
he corrected you and _you_ don't want to be considered to be under
his thumb.

What do you think about that?
 
B

Bob Monsen

[snip phase vs inversion discussion]
Admittedly, with a sine wave, they LOOK exactly the same; this is
probably the confusion factor for those who don't know the difference
yet.

All time based signals can be expressed as a sum of sine waves. By
superposition, each of those sin waves have been inverted by your inverter,
and so they each 'look' like they are all individually 180 degrees out of
phase... are they?

The concept of phase only applies to a single frequency. But, inverting a
signal appears to change the phase of all components by 180 degrees...

Turns out that there is an old psychology experiment, in which folks went
around wearing glasses that made everything look like it was upside-down.
After a few days, they got used to it, and everything looked right-side-up
with the glasses on, whereas when they took the glasses off, everything was
upside down. So, the question is, are you currently seeing things right side
up or upside down?

Are your glasses half-full? or half empty? Which end of the egg should be
opened first? Are you a big-endian, or a little-endian?

Pick your sides now. It is important to make sure you are on the right (or
would that be the left?) side.

:)
 
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