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Adding Up Battery Amp-Hours?

  • Thread starter Antipodean Bucket Farmer
  • Start date
A

Antipodean Bucket Farmer

Hi, Everybody,

Let's say that I want to make a small 12-volt battery
supply. So I use a pair of cheap 6-volt sealed gel
cells, in series.

Each of the two batteries is rated at, say,
5 Amp-Hours.

Will they add together, for a total of 10 Amp-Hours?
Or will the pair just provide 5 AH at the higher
voltage (I.e. 12-volts)?

Thanks...
 
G

GeekBoy

yes that is correct as voltage and amp are inverse of each other. As the
voltage increases the amperage decreases.

Try 4 batteries in series-parallel.
,>>
 
V

Vaughn

GeekBoy said:
yes that is correct as voltage and amp are inverse of each other. As the
voltage increases the amperage decreases.


HUH? Actually, current (amperage) is directly proportional to voltage and
inversly proportional to resistance.
I (current) = E (voltage) / R (resistance)


Vaughn
 
R

Ralph Cameron

Each cell is rated at 5 AH so in series they will provide double the voltage
but the same 5 AH.

If you parallel them you'll get 6V at 10AH
 
V

Vaughn

Just noticed that someone x-posted this thread. You can read any further
responses from me at alt.energy.homepower

Vaughn
 
V

Vaughn

GeekBoy said:
Check your forumula

I(current) = Watts / Volts

?(I) = 1000 / 120
?(I) = 1000 / 220

Using ohms law, if you have a 1000 watt hair dryer using 120 volts of
electricity that would result in 8.3 amps of current.
Increasing the voltage to 220 would result in 4.5 amps of current, making
voltage inversive to current. and vis-versa

Wrong. You are thinking about the power formula P = I X E

If you were to apply 220 volts to your 110 volt hairdryer, you would (for a
brief amount of time) have 16.66 amps and be producing 4000 watts of heat.
Shortly thereafter, the "magic smoke" would come out, and your hair dryer would
be toast. Current is proportional to voltage and always has been. Read up on
George Ohm's theory.

What you are trying to say is that a 220 volt 1000 watt heater will have half
the current (and twice the resistance) of a 110 volt 1000 watt heater. (P = I X
E) but I is still proportional to E.

Vaughn
 
S

Steve Spence

Antipodean said:
Hi, Everybody,

Let's say that I want to make a small 12-volt battery
supply. So I use a pair of cheap 6-volt sealed gel
cells, in series.

Each of the two batteries is rated at, say,
5 Amp-Hours.

Will they add together, for a total of 10 Amp-Hours?
Or will the pair just provide 5 AH at the higher
voltage (I.e. 12-volts)?

Thanks...

Two 6v 5ah in series is 12v 5ah.
Two 6v 5ah in parallel is 6v 10ah.
 
S

Steve Spence

GeekBoy said:
yes that is correct as voltage and amp are inverse of each other. As the
voltage increases the amperage decreases.

um, no. please try again. you are thinking of loads in watts.
 
S

Steve Spence

GeekBoy said:
Yes That is true.

Well, that has nothing to do with batteries in series or parallel. You
applied one concept to an unrelated problem.
 
K

K.A.M

Here are some wonderful handy BATTERY wiring diagrams for battery BANKS
Series & parallel

Kevin
 
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