Hi all,
New to forum and need some tech help. I am a marine engineer and a yachtie. Quite good with 12 volt electrics, but quickly out of my depth with electronics, so expect this will be basic for some of you guys and girls.
My question or problem is I have a 12 volt electric anchor winch that draws up to 100 amps when in use. This winch is controlled and feed by solenoids and a heavy gauge battery lead/wire. I have just installed a second smaller dinghy winch at the other end of the boat (14m away) and rather than run another heavy duty wire/cable, I have installed a local 12 volt battery charged by a 6mm tinned wire fed from the main winch circuit. This smaller winch draws about 30 amps during normal duty wth the wire length about 12 metres. To ensure the main winch doesn't draw from this localise battery I installed a 40 Amp Block Diode Cathode to Stud (which my understanding is the electronic equivalent of an engineering non return valve)to ensure this battery is isolated and that the lighter duty wire/cable is not subject to the amperage of the main winch when this is in use.
My question. Despite fitting the diode there is still some voltage present (leakage) around 4 volts up stream of the battery. This is isn't sufficient to worry the anchor winch, but annoyingly does illuminate the anchor winch led light which is a concern as this is the indicator that power is on to the winch (when it may not be) and a safety concern.
To overcome this, I have a) disconnected the local battery and current run the dinghy winch directly from the circuit. The rating for 6mm tinned wire appears to be 45 amps for separated wires, but 30 amps for twin flex which mine is. Given it only takes 40 seconds to raise the dinghy feel reasonably comfortable that the wire amperage is not overly excessive. Equally by fitting two 40 Amp Block Diode Cathode to Stud in series I have no voltage leakage.
Advice/comments most welcome?
New to forum and need some tech help. I am a marine engineer and a yachtie. Quite good with 12 volt electrics, but quickly out of my depth with electronics, so expect this will be basic for some of you guys and girls.
My question or problem is I have a 12 volt electric anchor winch that draws up to 100 amps when in use. This winch is controlled and feed by solenoids and a heavy gauge battery lead/wire. I have just installed a second smaller dinghy winch at the other end of the boat (14m away) and rather than run another heavy duty wire/cable, I have installed a local 12 volt battery charged by a 6mm tinned wire fed from the main winch circuit. This smaller winch draws about 30 amps during normal duty wth the wire length about 12 metres. To ensure the main winch doesn't draw from this localise battery I installed a 40 Amp Block Diode Cathode to Stud (which my understanding is the electronic equivalent of an engineering non return valve)to ensure this battery is isolated and that the lighter duty wire/cable is not subject to the amperage of the main winch when this is in use.
My question. Despite fitting the diode there is still some voltage present (leakage) around 4 volts up stream of the battery. This is isn't sufficient to worry the anchor winch, but annoyingly does illuminate the anchor winch led light which is a concern as this is the indicator that power is on to the winch (when it may not be) and a safety concern.
To overcome this, I have a) disconnected the local battery and current run the dinghy winch directly from the circuit. The rating for 6mm tinned wire appears to be 45 amps for separated wires, but 30 amps for twin flex which mine is. Given it only takes 40 seconds to raise the dinghy feel reasonably comfortable that the wire amperage is not overly excessive. Equally by fitting two 40 Amp Block Diode Cathode to Stud in series I have no voltage leakage.
Advice/comments most welcome?