Self assigned work, not homework, but seemed more appropriate to post here. I built a small circuit from a video course I have been watching. The assignment is below, but I modified it to work with parts I had on hand:
Namely, I didn't have an LDR nor a small incandescent bulb, so I just built a simple circuit using a switch (not shown) to mimic the on/off input of the LDR. For the two source voltages, I used a 5vdc source and a 9v battery (8.7vdc). The circuit is below. According to the program, the current at R1/D1 is 1.6mA, in reality when I built the circuit, I measured 0.34mA. The circuit functions as far as I can tell, the three LED's light when power is applied to the base of the transistor, so I assume the their is flow from collector to emitter. I was expecting to see more current.
Is the current of the top rail derived by dividing the final voltage (after the voltage drop of each diode and resistor) by the 1k resistor?
As for the paper exercise of the above - I assumed a beta of ~100 for the transistor and then set the resistor attached to the base to allow 2.5mA to pass. I used 4.3v/1720Ω = 0.0025A and with a 100 gain, it should allow 0.25A to pass between collector and emitter.
Namely, I didn't have an LDR nor a small incandescent bulb, so I just built a simple circuit using a switch (not shown) to mimic the on/off input of the LDR. For the two source voltages, I used a 5vdc source and a 9v battery (8.7vdc). The circuit is below. According to the program, the current at R1/D1 is 1.6mA, in reality when I built the circuit, I measured 0.34mA. The circuit functions as far as I can tell, the three LED's light when power is applied to the base of the transistor, so I assume the their is flow from collector to emitter. I was expecting to see more current.
Is the current of the top rail derived by dividing the final voltage (after the voltage drop of each diode and resistor) by the 1k resistor?
As for the paper exercise of the above - I assumed a beta of ~100 for the transistor and then set the resistor attached to the base to allow 2.5mA to pass. I used 4.3v/1720Ω = 0.0025A and with a 100 gain, it should allow 0.25A to pass between collector and emitter.