MeSoDumm said:
I've made my Hydrogen generator, but I am having an issue with the
wires heating up really bad!! What do I need to do?? I have hooked
it up to 12 volts and it puts out 993ml per minute, when i hook it up
to 6 volts it cuts it to 422ml per minute. What should the ohms
resistance be? or does that matter? Thx for all the help!!
Ohms law!
V/I = R
P = V^2/R = I^2*R
Either cut down V, which cuts down I or decrease R!!!!
If you need that much current(as you essetnially cut I in half and got about
half the amount of hydrogen) or cut R
Its much easier to cut I if you can.
You can use several smaller generators instead of one large one.
Essentially you can run 4 generators at half the current/voltage for the
same "heat price" at one but get twice as much hydrogen.
e.g., run 2 smaller generators at half the voltage, get 1/2 the "heat"(1/4
per generator) and get the same amount of hydrogen. (assumes current and
resistance do not change)
Decreasing R will decreasing the heat dissipated (P = I^2*R) but you must
decrease V too!!! (else I increases!!)
So, say you have V = 12V, R = 1ohm
This gives
I = 12A and P = 144W
Now if you decrease R by 1/2 so R = 0.5ohm
then
I = 24A and P = 288W. (V is still 12V)
But if you make V = 6V the
I = 12A and P = 72W!
So same current in first one but half the voltage and half the resistance
will cut the power in half! (and you'll still get the same amount of
hydrogen!!)
Point being that you have control of V and R but I and P depend on them. You
can play around with V and R to get what you want.
You can also solve for I and P such that
R = P/I^2
V = P/I
So if you want 36W dissipation and 12A current then
R = 1/4Ohm
V = 3V
(note same current as all the other examples but lower power
dissipation(heat in the wires(and larger wires)))