phase voltage

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If the following equation gives the phase voltage for a PMAC when the phase current (Iph) is in phase with the back emf (Eph)

Vph = (Eph + Rs*Iph) + j*2*pi*frequency in hertz*Ls*Iph

how would equation change when the Iph is 180 degrees out of phase with the back emf?

 

[Don Kelly]

If the following equation gives the phase voltage for a PMAC when the phase current (Iph) is in phase with the back emf (Eph)

Vph = (Eph + Rs*Iph) + j*2*pi*frequency in hertz*Ls*Iph

how would equation change when the Iph is 180 degrees out of phase with the back emf?

replace Iph by -Iph or + by -