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Non contact AC voltage tester

Hi all,
I recently made a non contact AC voltage tester with IC 4017. It works well . In the video that I saw the person told that the clock input of this ic would detect the emf produced which causes the LED to blink at a higher rate. My circuit works just as he said but it also detect DC voltages that are produced in AC to DC adaptor. How is that able to detect DC voltages? If so it detects then why only the DC current produced in adaptors and not in normal DC batteries? Please help not able to understand the logic behind.
The video is :
 
AC-DC adapters are not usually well screened, so stray radiated EM fields are present which can be picked up by your body and by nearby wires, such as the one you are holding in the pic.
 

davenn

Moderator
AC-DC adapters are not usually well screened, so stray radiated EM fields are present which can be picked up by your body and by nearby wires, such as the one you are holding in the pic.

yup as a result, any reading you got would be totally unreliable
 
The power supply to a microcontroller needs to be well decoupled (using low-impedance capacitors) so that stray EM fields are 'shorted to ground' and don't adversely affect the micro's performance.
 
The power supply to a microcontroller needs to be well decoupled (using low-impedance capacitors) so that stray EM fields are 'shorted to ground' and don't adversely affect the micro's performance.
Does the value of capacitors used in decoupling differ for different IC 's?
 
In general, yes. ICs drawing heavy current will normally require greater decoupling than those drawing light current.
 
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