A
alex
I have bought a PDA (acer n300), and I can find nothing details about
its battery.
It is written on the back of the battery pack that:
Model NO: BA-1405106
Product Name: Acer n300 battery pack, rechargeable lithium-ion
battery
Rating: DC 3.7v 1200mAh
At the bottom of the battery, there are 6 pins (3 pins each side).
| | | | | |
a b c d e f
After charging the battery, I measured the tensions between all of
these pins. And I got the following results: condition 1: unused
situation
Condition 2: under use situation (while
the PDA works)
1) +
a
b 0
c 0 0
d 1.2/3.7 4 4
e 1.2/3.7 4 4 0
f 0 0 0 -4 -4
- a b c d e
f
2 ) +
a
b -3.2
c -3.2 0
d 0.6 4 4
e 0.6 4 4 0
f -3.2 0 0 -4 -4
- a b c d e
f
In condition 1, the tensions between the Pin A and D, the Pin A and E
vary in the two fixed values 1.2 and 3.7
And in condition 2, all of the tensions who are measured with Pin A
have descended by -3.2 v.
Is there anyone who can explain why this battery behaves like this? Or
maybe someone has some technical sheet about this battery pack. Tell
me about it please !
Thank you in advance.
its battery.
It is written on the back of the battery pack that:
Model NO: BA-1405106
Product Name: Acer n300 battery pack, rechargeable lithium-ion
battery
Rating: DC 3.7v 1200mAh
At the bottom of the battery, there are 6 pins (3 pins each side).
| | | | | |
a b c d e f
After charging the battery, I measured the tensions between all of
these pins. And I got the following results: condition 1: unused
situation
Condition 2: under use situation (while
the PDA works)
1) +
a
b 0
c 0 0
d 1.2/3.7 4 4
e 1.2/3.7 4 4 0
f 0 0 0 -4 -4
- a b c d e
f
2 ) +
a
b -3.2
c -3.2 0
d 0.6 4 4
e 0.6 4 4 0
f -3.2 0 0 -4 -4
- a b c d e
f
In condition 1, the tensions between the Pin A and D, the Pin A and E
vary in the two fixed values 1.2 and 3.7
And in condition 2, all of the tensions who are measured with Pin A
have descended by -3.2 v.
Is there anyone who can explain why this battery behaves like this? Or
maybe someone has some technical sheet about this battery pack. Tell
me about it please !
Thank you in advance.