Max Vout of current monitor?

[eem2am]

Hello,
I am using ZXCT1009 to monitor current flow from a 3V battery.
What is the maximum voltage that Vout of zxct1009 can be?
(i.e. the voltage at the "iout" pin.)

I.e supposing current from the "iout" pin is 1mA...then how big can i make the output resistor?.....would 1K8 be ok? Whats the highest resistance it could be?

ZXCT1009 Datasheet
http://www.diodes.com/datasheets/ZXCT1009.pdf

 

[CDRIVE]

It's a current output, so output voltage isn't specified. Therefore Eout = (Iout * Rout). The value of Rout isn't specified either, as it will depend on the voltage you want to develop across the Rout. At least that's my take on the specs.

Chris

 

[eem2am]

The datasheet on oage 5 speaks of a dropout voltage "VDP", but doesnt state what it is......there must be some working "headroom" required by the part?

If the " iout" resistor was 2.5mA and the v+ was 2.5V then the current into it could never be 1mA since this gives no "Headroom"?
But the datasheet doesnt state what is the headroom voltage?

 

[Harald Kapp]

The "headroom" is the min. Vcc=2.5V (page 2, table electrical characteristics). This is the minimum voltage that will drop from the Vin pin to the Iout pin. Therefore Vout=Iout*Rout <=(Vin-2.5V) needs to be fulfilled.
The application information on page 4 tells you how to calculate the required resistors.