IC 4511

[vick5821]

Hey guys,

I read something about 7 segment. It can be controlled based on logic. Combination of logic. I used an IC 4511 with 4 switch to display the numbers from 0 to 9. However, I do not understand actually how the internal logics work ? Can anyon explain to me ?

(Is it the simplfied expression I have to build a circuit using logic gates instead of using IC 4511?

Thank you

 

[(*steve*)]

Hey, you've been here long enough to know to put this in homework help!

That expression is for a single segment of the 7 segment display.

If you look at the binary number representation of 0 to 9 and compare this with the segments you want to light for each one, this logic is sufficient for just one of those segments.

As for your question. I don't know. Nothing in the question tells me that you need to do anything, so I can't comment on what it might be that you need to do. However I suspect that it would NOT involve a 4511.

 

[vick5821]

Hey, you've been here long enough to know to put this in homework help!

That expression is for a single segment of the 7 segment display.

If you look at the binary number representation of 0 to 9 and compare this with the segments you want to light for each one, this logic is sufficient for just one of those segments.

As for your question. I don't know. Nothing in the question tells me that you need to do anything, so I can't comment on what it might be that you need to do. However I suspect that it would NOT involve a 4511.

SO for the case of in the attached picture, it does not involve 4511 but we need to make a combinational logic circuit consists of ABCD as the input ? Am I correct ?

Thank you.

sorry steve

 

[(*steve*)]

It would seem likely, but you have not postd the actual question, only the preamble, so I can't be sure.

You might have to only implement a single segment, or you may have to implement all of them.

Or you may have to do something else entirely.

 

[vick5821]

It would seem likely, but you have not postd the actual question, only the preamble, so I can't be sure.

You might have to only implement a single segment, or you may have to implement all of them.

Or you may have to do something else entirely.

I mean I need to construct a circuit with all the logic gates to apply the simplified SOP expression to get the segment a to lights up ?

 

[vick5821]

http://www.allaboutcircuits.com/vol_6/chpt_7/9.html

Refer to this website, for the below statement, I do not understand it. What does invoke that function means actually ? To operate ? Sounds weird

Once again, the manufacturer's datasheet will be informative as to the purpose of each of these three inputs. Note that the "Lamp Test" (LT) and "Blanking Input" (BI) input labels are written with boolean complementation bars over the abbreviations. Bar symbols designate these inputs as active-low, meaning that you must make each one "low" in order to invoke its particular function. Making an active-low input "high" places that particular input into a "passive" state where its function will not be invoked. Conversely, the "Latch Enable" (LE) input has no complementation bar written over its abbreviation, and correspondingly it is shown connected to ground ("low") in the schematic so as to not invoke that function. The "Latch Enable" input is an active-high input, which means it must be made "high" (connected to Vdd) in order to invoke its function.

Thank you

 

[War_Spigot]

There's a logic diagram of it in the datasheet, if that's what you're looking for.

 

[(*steve*)]

And there's also the boolean algebra in the first post that just needs to be converted into reality using a few gates. (which I think is the answer)

Hint + = and OR gate
a bar indicates an inverter
multiplication is the AND function

A, B, C, and D are the 4 binary digits.