Hi. I am very new to this, so please excuse any faux pas.
I am trying to connect a pure sine wave 240v inverter into my caravan, but I don't want the current to flow back to the inverter. At the same time I want to limit the current/ wattage output of the inverter.
To limit the output I was going to connect a 5 or 10 w light bulb in series, and to prevent any current flow back to the inverter I thought maybe a diode? Or perhaps I don't need that? Any help would be appreciated.
Thanks
Lets start by clearing a couple misunderstandings.
Current flow is caused by electricity flowing from a higher voltage to a lower voltage... ie, from the + side of a batter through the electronics and to the - side of the battery.
The only way for current to flow backward in this example is if something connected to the electronics produce a higher voltage than the battery, then it will flow from the higher voltage in to the + side of the battery...
This is rarely a concern with electronics except for where 'inductive loads' are concerned... Like power tools... The motors are built in such a way that if you turn them off, they can potentially produce a much higher voltage which will feed back into the system.
Now... the thing is, with AC, current is meant to flow backwards and forwards. That's the entire point of AC. In this situation, large inductive loads should be tuned in such a way with inductors and/or capacitors to reduce the amount of feedback that goes back into the lines... sometimes this can't be helped which is why you may notice lights flicker when you turn your vacuum off.
So, if you want any kind of protection, you will need to put it on the DC side of the inverter... but be warned the diode will cause a small amount of voltage to be lost which may hinder the performance of the inverter. (Probably not... but I grew up around car audio guys who claim it makes a difference... it does, but not any amount to be noticeable or a problem)
So let's move on to power now... What it is and how you can control it.
Power is the product of Voltage and Current. So you
give 12V to a light-bulb and it
takes 2 Amps. The power here will be 24 Watts.
How do you lower the Power here? Well... you can lower the voltage, or lower the amperage... Notice how I worded that though...
The light-bulb will only
take what it needs, based on it's internal resistance. The light-bulb is a pretty dumb device though... so if you put something in-line with it... like another light bulb, only 6V will go to each light-bulb. This will result in the light-bulb only taking 1 Amp. This again, is because the light-bulb is a basic device and the amperage taken is a direct result of it's resistance. The formula for that is here : Voltage = Current * Resistance.
In this example the light-bulb has a resistance of 6Ω, it's set, so in order to change power to it we need to control how much voltage we give it. It will take care of how much current it takes by itself.
There is a little problem though... The Inverter is not a basic component... just like a car amplifier is not a basic component... They have active electronics inside that will constantly change the device's internal resistance to pull more or less amperage as it needs it. If you give it a lower voltage, it will try to take more amperage to compensate. If it want's to put out 60 Watts it's going to try it's hardest... and if the voltage goes too low the electronics may be smart enough to detect a problem and shut down completely.
If you want to limit the output power of the inverter, simply don't plug a really heavy load into it like a microwave or 4-burner cook-top
The alternative would be to buy a smaller inverter that outputs less current. Remember here that the 'Wattage' of an inverter is what it is capable of, not what it will always be running at. Just like your Van, the engine does not always operate at it's peak Horsepower and Torque ratings until you make it.
Additionally, I really don't think you will need a diode for your inverter, but if you want to be cautious it's fine by me... just remember to find one that can handle the load...
A 60 Watt light-bulb will pull over 5 Amps into the inverter from the 12V battery. If you have a 600W inverter... be prepared to find and install a diode larger than 50A.
(I don't know what kind you have... but you should look at what may be required.)
Some extra protection you CAN rely on though would be an undersized fuse... I'm both for and against this idea though... You can size it in such a way that the fuse will pop if the inverter tries to pull too much current, but if anyone other than you looks at the rating on the inverter, they will assume the rated power is available to use and unintentionally pop the fuse. This is an all or nothing approach that would create that limitation you wanted, but would require fuse replacements if someone goes over the limit.
Anyway, give that a read and see if any more questions or ideas pop into your head.