I have built a circuit that can be simplified to the layout in the link below: -
https://www.dropbox.com/s/e0jl8ds0dw0ucx0/CircuitQ.png?dl=0
When I put in a triangular wave voltage input, the output looks similar to the one I have sketched on my drawing. I am trying to understand why it behaves like this, please can someone help?
I know that for a single capacitor the output should be a square wave because I = C* d(V)/dt and d(V)/dt is constant - with an amplitude which depends on the value of C. For a single resistor I think I should see a triangular wave with zero phase shift between the voltage input and current output. I can understand that the output is some form of combination of these two effects, but I don't understand much more than that.
Please can someone help me to get a better idea of what is happening, is there any way to calculate what a and b would be if I knew the values of the capacitors and resistors without building the circuit again and measuring? I assume this would also be dependent on the frequency of the input signal because with a very low frequency I can see the current would eventually reach zero before the voltage switches sign again....
Also, should the slopes in the output be linear? They looked very slightly curved on the oscilloscope, I may have mis-read.
Thank you
https://www.dropbox.com/s/e0jl8ds0dw0ucx0/CircuitQ.png?dl=0
When I put in a triangular wave voltage input, the output looks similar to the one I have sketched on my drawing. I am trying to understand why it behaves like this, please can someone help?
I know that for a single capacitor the output should be a square wave because I = C* d(V)/dt and d(V)/dt is constant - with an amplitude which depends on the value of C. For a single resistor I think I should see a triangular wave with zero phase shift between the voltage input and current output. I can understand that the output is some form of combination of these two effects, but I don't understand much more than that.
Please can someone help me to get a better idea of what is happening, is there any way to calculate what a and b would be if I knew the values of the capacitors and resistors without building the circuit again and measuring? I assume this would also be dependent on the frequency of the input signal because with a very low frequency I can see the current would eventually reach zero before the voltage switches sign again....
Also, should the slopes in the output be linear? They looked very slightly curved on the oscilloscope, I may have mis-read.
Thank you