I am doing a fairly simple project.
Basically I am charging a 300F 2.3V max supercapacitor with a 2V solar cell array to run a small 1.5V radio. I already tested the cap with the radio by charging it with an alkaline battery. The radio already seems to have a boost circuit to keep the volume fairly constant until the end so that is fine, no external boost circuitry needed.
What I simply need is a diode to prevent the supercap from losing its charge by leaking back through the solar cells when in the dark.
The ideal diode would have a voltage drop (loss) as low as possible so the solar cells charge the cap more instead of wasting voltage running the diode (needing more solar cells and increasing unit size). It would also have a good leakage protection so the cap discharges back through the cells as little as possible.
The solar cell array produces 300 mA @ 2.2V in full sun. I need a diode as close to this as possible (larger ones waste more forward voltage).
What do you recommend? Part numbers and where to get would help even more.
Thanks.
Basically I am charging a 300F 2.3V max supercapacitor with a 2V solar cell array to run a small 1.5V radio. I already tested the cap with the radio by charging it with an alkaline battery. The radio already seems to have a boost circuit to keep the volume fairly constant until the end so that is fine, no external boost circuitry needed.
What I simply need is a diode to prevent the supercap from losing its charge by leaking back through the solar cells when in the dark.
The ideal diode would have a voltage drop (loss) as low as possible so the solar cells charge the cap more instead of wasting voltage running the diode (needing more solar cells and increasing unit size). It would also have a good leakage protection so the cap discharges back through the cells as little as possible.
The solar cell array produces 300 mA @ 2.2V in full sun. I need a diode as close to this as possible (larger ones waste more forward voltage).
What do you recommend? Part numbers and where to get would help even more.
Thanks.
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