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Getting crazy with an AD590

R

rossi

Getting crazy with an AD590JH simply connected to a resistor of 11k/1% :

+5V----
|
AD590
|
-------*-------------o
11kOhm ^
-- Vo
| |
--- 0V --- 0V



Vo should be about 11mV/K but I measure 2.7V as indoor temperature
(-24 °C!!).

According to you, where I'm wrong?

Thanks in advance
 
D

Dave (from the UK)

rossi said:
Getting crazy with an AD590JH simply connected to a resistor of 11k/1% :

+5V----
|
AD590
|
-------*-------------o
11kOhm ^
-- Vo
| |
--- 0V --- 0V



Vo should be about 11mV/K but I measure 2.7V as indoor temperature
(-24 °C!!).

According to you, where I'm wrong?

Thanks in advance

My guess is that the resistor is too high given the suply voltage you
have. I'd suggest decreating the resistor or increasing the supply
voltage. The device needs a suppy voltage of 4 to 30 V, but with a 11 K
resistor you have a lot less than that across the device.

--
Dave K MCSE.

MCSE = Minefield Consultant and Solitaire Expert.

Please note my email address changes periodically to avoid spam.
It is always of the form: month-year@domain. Hitting reply will work
for a couple of months only. Later set it manually.
 
A

amdx

rossi said:
Getting crazy with an AD590JH simply connected to a resistor of 11k/1% :

+5V----
|
AD590
|
-------*-------------o
11kOhm ^
-- Vo
| |
--- 0V --- 0V



Vo should be about 11mV/K but I measure 2.7V as indoor temperature
(-24 °C!!).

According to you, where I'm wrong?

Thanks in advance

The Analog Devices pdf shows a series resistor of about
1000 ohms with a 6 volt supply.
 
Z

ZeroDue

amdx ha scritto:
The Analog Devices pdf shows a series resistor of about
1000 ohms with a 6 volt supply.

Ok, I'll try. Is there some formula to obtain the resistor according to
the supply?

Thanks to all.
 
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